is_polymorphic template in C++
The std::is_polymorphic template of C++ STL is used to checks whether the type is a polymorphic class type or not. It returns a boolean value showing the same.
Syntax:
template < class T > struct is_polymorphic;
Parameter: This template contains single parameter T (Trait class) to check whether T is a polymorphic class type or not.
Return Value:This template returns a boolean value as shown below:
- True: if the type is a polymorphic class.
- False: if the type is a non-polymorphic class.
Below programs illustrate the std::is_polymorphic template in C++ STL:
Program 1:
#include <iostream>
#include <type_traits>
using namespace std;
struct gfg {
virtual void foo();
};
struct geeks : gfg {
};
class raj {
virtual void foo() = 0;
};
struct sam : raj {
};
int main()
{
cout << boolalpha;
cout << "is_polymorphic:"
<< '\n' ;
cout << "gfg:"
<< is_polymorphic<gfg>::value
<< '\n' ;
cout << "geeks:"
<< is_polymorphic<geeks>::value
<< '\n' ;
cout << "raj:"
<< is_polymorphic<raj>::value
<< '\n' ;
cout << "sam:"
<< is_polymorphic<sam>::value
<< '\n' ;
return 0;
}
|
Output:
is_polymorphic:
gfg:true
geeks:true
raj:true
sam:true
Program 2:
#include <iostream>
#include <type_traits>
using namespace std;
struct gfg {
int m;
};
struct sam {
virtual void foo() = 0;
};
class raj : sam {
};
int main()
{
cout << boolalpha;
cout << "is_polymorphic:"
<< '\n' ;
cout << "gfg:"
<< is_polymorphic<gfg>::value
<< '\n' ;
cout << "sam:"
<< is_polymorphic<sam>::value
<< '\n' ;
cout << "raj:"
<< is_polymorphic<raj>::value
<< '\n' ;
return 0;
}
|
Output:
is_polymorphic:
gfg:false
sam:true
raj:true
Last Updated :
19 Nov, 2018
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