# Inverse Error Function of Given Number in Golang

Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the inverse error function of the specified number with the help of Erfinv() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the Erfinv() function.

Syntax:

`func Erfinv(a float64) float64`
• If you pass 1 in this function, then this function will return +Inf.
• If you pass -1 in this function, then this function will return -Inf.
• If you pass NaN in this function, then this function will return NaN.
• If the value of a < -1 or a > 1 in this function, then this function will return NaN.

Example 1:

 `// Golang program to illustrate how to find ` `// the inverse error function of the ` `// given number ` `  `  `package main ` `  `  `import ( ` `    ``"fmt"` `    ``"math"` `) ` `  `  `// Main function ` `func main() { ` `  `  `    ``// Finding inverse error function ` `    ``// Using Erfinv() function ` `    ``res_1 := math.Erfinv(0.968) ` `    ``res_2 := math.Erfinv(1) ` `    ``res_3 := math.Erfinv(-1) ` `    ``res_4 := math.Erfinv(math.NaN()) ` `  `  `    ``// Displaying the result ` `    ``fmt.Printf(``"Result 1: %.1f"``, res_1) ` `    ``fmt.Printf(``"\nResult 2: %.1f"``, res_2) ` `    ``fmt.Printf(``"\nResult 3: %.1f"``, res_3) ` `    ``fmt.Printf(``"\nResult 4: %.1f"``, res_4) ` `  `  `} `

Output:

```Result 1: 1.5
Result 2: +Inf
Result 3: -Inf
Result 4: NaN
```

Example 2:

 `// Golang program to illustrate how to find ` `// the inverse error function of the ` `// given number ` `  `  `package main ` `  `  `import ( ` `    ``"fmt"` `    ``"math"` `) ` `  `  `// Main function ` `func main() { ` `  `  `    ``// Finding inverse error function ` `    ``// Using Erfc() function ` `    ``nvalue_1 := math.Erfinv(0.5475) ` `    ``nvalue_2 := math.Erfinv(0.28547) ` `    ``res := nvalue_1 + nvalue_2 ` `    ``fmt.Printf(``"%.1f + %.1f = %.1f"``, ` `            ``nvalue_1, nvalue_2, res) ` `  `  `} `

Output:

`0.5 + 0.3 = 0.8`

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