We are given two numbers n and m, and two-bit positions, i and j. Insert bits of m into n starting from j to i. We can assume that the bits j through i have enough space to fit all of m. That is, if m = 10011, you can assume that there are at least 5 bits between j and i. You would not, for example, have j = 3 and i = 2, because m could not fully fit between bit 3 and bit 2.

Examples :

Input : n = 1024 m = 19 i = 2 j = 6; Output : n = 1100 Binary representations of input numbers m in binary is (10011)_{2}n in binary is (10000000000)_{2}Binary representations of output number (10000000000)_{2}Input : n = 5 m = 3 i = 1 j = 2 Output : 7

**Algorithm :**

1. Clear the bits j through i in n 2. Shift m so that it lines up with bits j through i 3. Return Bitwise AND of m and n.

The trickiest part is Step 1. How do we clear the bits in n? We can do this with a mask. This mask will have all 1s, except for 0s in the bits j through i. We create this mask by creating the left half of the mask first, and then the right half.

Following is the implementation of the above approach.

## C++

`// C++ program for implementation of updateBits() ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to updateBits M insert to N. ` `int` `updateBits(` `int` `n, ` `int` `m, ` `int` `i, ` `int` `j) ` `{ ` ` ` `/* Create a mask to clear bits i through j ` ` ` `in n. EXAMPLE: i = 2, j = 4. Result ` ` ` `should be 11100011. For simplicity, we'll ` ` ` `use just 8 bits for the example. */` ` ` ` ` `int` `allOnes = ~0; ` `// will equal sequence of all ls ` ` ` ` ` `// ls before position j, then 0s. left = 11100000 ` ` ` `int` `left= allOnes << (j + 1); ` ` ` ` ` `// l's after position i. right = 00000011 ` ` ` `int` `right = ((1 << i) - 1); ` ` ` ` ` `// All ls, except for 0s between i and j. mask 11100011 ` ` ` `int` `mask = left | right; ` ` ` ` ` `/* Clear bits j through i then put min there */` ` ` `int` `n_cleared = n & mask; ` `// Clear bits j through i. ` ` ` `int` `m_shifted = m << i; ` `// Move m into correct position. ` ` ` ` ` `return` `(n_cleared | m_shifted); ` `// OR them, and we're done! ` `} ` ` ` `// Driver Code ` `int` `main() ` `{ ` ` ` `int` `n = 1024; ` `// in Binary N= 10000000000 ` ` ` `int` `m = 19; ` `// in Binary M= 10011 ` ` ` `int` `i = 2, j = 6; ` ` ` ` ` `cout << updateBits(n,m,i,j); ` ` ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program for implementation of updateBits() ` ` ` `class` `UpdateBits ` `{ ` ` ` `// Function to updateBits M insert to N. ` ` ` `static` `int` `updateBits(` `int` `n, ` `int` `m, ` `int` `i, ` `int` `j) ` ` ` `{ ` ` ` `/* Create a mask to clear bits i through j ` ` ` `in n. EXAMPLE: i = 2, j = 4. Result ` ` ` `should be 11100011. For simplicity, we'll ` ` ` `use just 8 bits for the example. */` ` ` ` ` `int` `allOnes = ~` `0` `; ` `// will equal sequence of all ls ` ` ` ` ` `// ls before position j, then 0s. left = 11100000 ` ` ` `int` `left= allOnes << (j + ` `1` `); ` ` ` ` ` `// l's after position i. right = 00000011 ` ` ` `int` `right = ((` `1` `<< i) - ` `1` `); ` ` ` ` ` `// All ls, except for 0s between i and j. mask 11100011 ` ` ` `int` `mask = left | right; ` ` ` ` ` `/* Clear bits j through i then put min there */` ` ` `// Clear bits j through i. ` ` ` `int` `n_cleared = n & mask; ` ` ` `// Move m into correct position. ` ` ` `int` `m_shifted = m << i; ` ` ` ` ` `// OR them, and we're done! ` ` ` `return` `(n_cleared | m_shifted); ` ` ` `} ` ` ` ` ` `public` `static` `void` `main (String[] args) ` ` ` `{ ` ` ` `// in Binary N= 10000000000 ` ` ` `int` `n = ` `1024` `; ` ` ` ` ` `// in Binary M= 10011 ` ` ` `int` `m = ` `19` `; ` ` ` ` ` `int` `i = ` `2` `, j = ` `6` `; ` ` ` ` ` `System.out.println(updateBits(n,m,i,j)); ` ` ` `} ` `} ` |

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## Python3

`# Python3 program for implementation ` `# of updateBits() ` ` ` `# Function to updateBits M insert to N. ` `def` `updateBits(n, m, i, j): ` ` ` ` ` `# Create a mask to clear bits i through ` ` ` `# j in n. EXAMPLE: i = 2, j = 4. Result ` ` ` `# should be 11100011. For simplicity, ` ` ` `# we'll use just 8 bits for the example. ` ` ` ` ` `# will equal sequence of all ls ` ` ` `allOnes ` `=` `~` `0` ` ` ` ` `# ls before position j, ` ` ` `# then 0s. left = 11100000 ` ` ` `left ` `=` `allOnes << (j ` `+` `1` `) ` ` ` ` ` `# l's after position i. right = 00000011 ` ` ` `right ` `=` `((` `1` `<< i) ` `-` `1` `) ` ` ` ` ` `# All ls, except for 0s between ` ` ` `# i and j. mask 11100011 ` ` ` `mask ` `=` `left | right ` ` ` ` ` `# Clear bits j through i then put min there ` ` ` `n_cleared ` `=` `n & mask ` ` ` ` ` `# Move m into correct position. ` ` ` `m_shifted ` `=` `m << i ` ` ` ` ` `return` `(n_cleared | m_shifted) ` ` ` ` ` `# Driver Code ` `n ` `=` `1024` `# in Binary N = 10000000000 ` `m ` `=` `19` `# in Binary M = 10011 ` `i ` `=` `2` `; j ` `=` `6` `print` `(updateBits(n, m, i, j)) ` ` ` `# This code is contributed by Anant Agarwal. ` |

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## C#

`// C# program for implementation of ` `// updateBits() ` `using` `System; ` ` ` `class` `GFG { ` ` ` ` ` `// Function to updateBits M ` ` ` `// insert to N. ` ` ` `static` `int` `updateBits(` `int` `n, ` `int` `m, ` ` ` `int` `i, ` `int` `j) ` ` ` `{ ` ` ` ` ` `/* Create a mask to clear bits i ` ` ` `through j in n. EXAMPLE: i = 2, ` ` ` `j = 4. Result should be 11100011. ` ` ` `For simplicity, we'll use just 8 ` ` ` `bits for the example. */` ` ` ` ` `// will equal sequence of all ls ` ` ` `int` `allOnes = ~0; ` ` ` ` ` `// ls before position j, then 0s. ` ` ` `// left = 11100000 ` ` ` `int` `left= allOnes << (j + 1); ` ` ` ` ` `// l's after position i. ` ` ` `// right = 00000011 ` ` ` `int` `right = ((1 << i) - 1); ` ` ` ` ` `// All ls, except for 0s between i ` ` ` `// and j. mask 11100011 ` ` ` `int` `mask = left | right; ` ` ` ` ` `/* Clear bits j through i then put ` ` ` `min there */` ` ` `// Clear bits j through i. ` ` ` `int` `n_cleared = n & mask; ` ` ` ` ` `// Move m into correct position. ` ` ` `int` `m_shifted = m << i; ` ` ` ` ` `// OR them, and we're done! ` ` ` `return` `(n_cleared | m_shifted); ` ` ` `} ` ` ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` ` ` `// in Binary N= 10000000000 ` ` ` `int` `n = 1024; ` ` ` ` ` `// in Binary M= 10011 ` ` ` `int` `m = 19; ` ` ` `int` `i = 2, j = 6; ` ` ` ` ` `Console.WriteLine(updateBits(n, m, i, j)); ` ` ` `} ` `} ` ` ` `//This code is contributed by Anant Agarwal. ` |

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## PHP

`<?php ` `// PHP program for implementation ` `// of updateBits() ` ` ` `// Function to updateBits ` `// M insert to N. ` ` ` `function` `updateBits(` `$n` `, ` `$m` `, ` `$i` `, ` `$j` `) ` `{ ` ` ` `// Create a mask to clear ` ` ` `// bits i through j in n. ` ` ` `// EXAMPLE: i = 2, j = 4. ` ` ` `// Result should be 11100011. ` ` ` `// For simplicity, we'll use ` ` ` `// just 8 bits for the example. ` ` ` ` ` `// will equal sequence of all ls ` ` ` `$allOnes` `= ~0; ` ` ` ` ` `// ls before position j, then ` ` ` `// 0s. left = 11100000 ` ` ` `$left` `= ` `$allOnes` `<< (` `$j` `+ 1); ` ` ` ` ` `// l's after position i. ` ` ` `// right = 00000011 ` ` ` `$right` `= ((1 << ` `$i` `) - 1); ` ` ` ` ` `// All ls, except for 0s between ` ` ` `// i and j. mask 11100011 ` ` ` `$mask` `= ` `$left` `| ` `$right` `; ` ` ` ` ` `// Clear bits j through i ` ` ` `// then put min there ` ` ` ` ` `// Clear bits j through i. ` ` ` `$n_cleared` `= ` `$n` `& ` `$mask` `; ` ` ` ` ` `// Move m into correct position. ` ` ` `$m_shifted` `= ` `$m` `<< ` `$i` `; ` ` ` ` ` `// OR them, and we're done! ` ` ` `return` `(` `$n_cleared` `| ` `$m_shifted` `); ` `} ` ` ` `// Driver Code ` ` ` `// in Binary N= 10000000000 ` `$n` `= 1024; ` ` ` `// in Binary M= 10011 ` `$m` `= 19; ` `$i` `= 2; ` `$j` `= 6; ` ` ` `echo` `updateBits(` `$n` `, ` `$m` `, ` `$i` `, ` `$j` `); ` ` ` `// This code is contributed by Ajit ` `?> ` |

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**Output :**

1100 // in Binary (10001001100)_{2}

This article is contributed by **Mr. Somesh Awasthi**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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