Insert node into the middle of the linked list
Given a linked list containing n nodes. The problem is to insert a new node with data x at the middle of the list. If n is even, then insert the new node after the (n/2)th node, else insert the new node after the (n+1)/2th node.
Examples:
Input : list: 1->2->4->5
x = 3
Output : 1->2->3->4->5
Input : list: 5->10->4->32->16
x = 41
Output : 5->10->4->41->32->16
Method 1(Using length of the linked list):
Find the number of nodes or length of the linked using one traversal. Let it be len. Calculate c = (len/2), if len is even, else c = (len+1)/2, if len is odd. Traverse again the first c nodes and insert the new node after the cth node.
C++
// C++ implementation to insert node at the middle // of the linked list #include <bits/stdc++.h> using namespace std; // structure of a node struct Node { int data; Node* next; }; // function to create and return a node Node* getNode(int data) { // allocating space Node* newNode = (Node*)malloc(sizeof(Node)); // inserting the required data newNode->data = data; newNode->next = NULL; return newNode; } // function to insert node at the middle // of the linked list void insertAtMid(Node** head_ref, int x) { // if list is empty if (*head_ref == NULL) *head_ref = getNode(x); else { // get a new node Node* newNode = getNode(x); Node* ptr = *head_ref; int len = 0; // calculate length of the linked list //, i.e, the number of nodes while (ptr != NULL) { len++; ptr = ptr->next; } // 'count' the number of nodes after which // the new node is to be inserted int count = ((len % 2) == 0) ? (len / 2) : (len + 1) / 2; ptr = *head_ref; // 'ptr' points to the node after which // the new node is to be inserted while (count-- > 1) ptr = ptr->next; // insert the 'newNode' and adjust the // required links newNode->next = ptr->next; ptr->next = newNode; } } // function to display the linked list void display(Node* head) { while (head != NULL) { cout << head->data << " "; head = head->next; } } // Driver program to test above int main() { // Creating the list 1->2->4->5 Node* head = NULL; head = getNode(1); head->next = getNode(2); head->next->next = getNode(4); head->next->next->next = getNode(5); cout << "Linked list before insertion: "; display(head); int x = 3; insertAtMid(&head, x); cout << "\nLinked list after insertion: "; display(head); return 0; } |
chevron_right
filter_none
Java
// Java implementation to insert node // at the middle of the linked list import java.util.*; import java.lang.*; import java.io.*; class LinkedList { static Node head; // head of list /* Node Class */ static class Node { int data; Node next; // Constructor to create a new node Node(int d) { data = d; next = null; } } // function to insert node at the // middle of the linked list static void insertAtMid(int x) { // if list is empty if (head == null) head = new Node(x); else { // get a new node Node newNode = new Node(x); Node ptr = head; int len = 0; // calculate length of the linked list //, i.e, the number of nodes while (ptr != null) { len++; ptr = ptr.next; } // 'count' the number of nodes after which // the new node is to be inserted int count = ((len % 2) == 0) ? (len / 2) : (len + 1) / 2; ptr = head; // 'ptr' points to the node after which // the new node is to be inserted while (count-- > 1) ptr = ptr.next; // insert the 'newNode' and adjust // the required links newNode.next = ptr.next; ptr.next = newNode; } } // function to display the linked list static void display() { Node temp = head; while (temp != null) { System.out.print(temp.data + " "); temp = temp.next; } } // Driver program to test above public static void main (String[] args) { // Creating the list 1.2.4.5 head = null; head = new Node(1); head.next = new Node(2); head.next.next = new Node(4); head.next.next.next = new Node(5); System.out.println("Linked list before "+ "insertion: "); display(); int x = 3; insertAtMid(x); System.out.println("\nLinked list after"+ " insertion: "); display(); } } // This article is contributed by Chhavi |
chevron_right
filter_none
Python3
# Python3 implementation to insert node # at the middle of a linked list # Node class class Node: # constructor to create a new node def __init__(self, data): self.data = data self.next = None # function to insert node at the # middle of linked list given the head def insertAtMid(head, x): if(head == None): #if the list is empty head = Node(x) else: # create a new node for the value # to be inserted newNode = Node(x) ptr = head length = 0 # calcualte the length of the linked # list while(ptr != None): ptr = ptr.next length += 1 # 'count' the number of node after which # the new node has to be inserted if(length % 2 == 0): count = length / 2 else: (length + 1) / 2 ptr = head # move ptr to the node after which # the new node has to inserted while(count > 1): count -= 1 ptr = ptr.next # insert the 'newNode' and adjust # links accordingly newNode.next = ptr.next ptr.next = newNode # function to displat the linked list def display(head): temp = head while(temp != None): print(str(temp.data), end = " ") temp = temp.next # Driver Code # Creating the linked list 1.2.4.5 head = Node(1) head.next = Node(2) head.next.next = Node(4) head.next.next.next = Node(5) print("Linked list before insertion: ", end = "") display(head) # inserting 3 in the middle of the linked list. x = 3insertAtMid(head, x) print("\nLinked list after insertion: " , end = "") display(head) # This code is contributed by Pranav Devarakonda |
chevron_right
filter_none
C#
// C# implementation to insert node // at the middle of the linked list using System; public class LinkedList { static Node head; // head of list /* Node Class */ public class Node { public int data; public Node next; // Constructor to create a new node public Node(int d) { data = d; next = null; } } // function to insert node at the // middle of the linked list static void insertAtMid(int x) { // if list is empty if (head == null) head = new Node(x); else { // get a new node Node newNode = new Node(x); Node ptr = head; int len = 0; // calculate length of the linked list //, i.e, the number of nodes while (ptr != null) { len++; ptr = ptr.next; } // 'count' the number of nodes after which // the new node is to be inserted int count = ((len % 2) == 0) ? (len / 2) : (len + 1) / 2; ptr = head; // 'ptr' points to the node after which // the new node is to be inserted while (count-- > 1) ptr = ptr.next; // insert the 'newNode' and adjust // the required links newNode.next = ptr.next; ptr.next = newNode; } } // function to display the linked list static void display() { Node temp = head; while (temp != null) { Console.Write(temp.data + " "); temp = temp.next; } } // Driver code public static void Main () { // Creating the list 1.2.4.5 head = null; head = new Node(1); head.next = new Node(2); head.next.next = new Node(4); head.next.next.next = new Node(5); Console.WriteLine("Linked list before "+ "insertion: "); display(); int x = 3; insertAtMid(x); Console.WriteLine("\nLinked list after"+ " insertion: "); display(); } } /* This code contributed by PrinciRaj1992 */ |
chevron_right
filter_none
Output:
Linked list before insertion: 1 2 4 5 Linked list after insertion: 1 2 3 4 5
Time Complexity: O(n)
Method 2(Using two pointers):
Based on the tortoise and hare algorithm which uses two pointers, one known as slow and the other known as fast. This algorithm helps in finding the middle node of the linked list. It is explained in the front and black split procedure of this post. Now, you can insert the new node after the middle node obtained from the above process. This approach requires only a single traversal of the list.
C++
// C++ implementation to insert node at the middle // of the linked list #include <bits/stdc++.h> using namespace std; // structure of a node struct Node { int data; Node* next; }; // function to create and return a node Node* getNode(int data) { // allocating space Node* newNode = (Node*)malloc(sizeof(Node)); // inserting the required data newNode->data = data; newNode->next = NULL; } // function to insert node at the middle // of the linked list void insertAtMid(Node** head_ref, int x) { // if list is empty if (*head_ref == NULL) *head_ref = getNode(x); else { // get a new node Node* newNode = getNode(x); // assign values to the slow and fast // pointers Node* slow = *head_ref; Node* fast = (*head_ref)->next; while (fast && fast->next) { // move slow pointer to next node slow = slow->next; // move fast pointer two nodes at a time fast = fast->next->next; } // insert the 'newNode' and adjust the // required links newNode->next = slow->next; slow->next = newNode; } } // function to display the linked list void display(Node* head) { while (head != NULL) { cout << head->data << " "; head = head->next; } } // Driver program to test above int main() { // Creating the list 1->2->4->5 Node* head = NULL; head = getNode(1); head->next = getNode(2); head->next->next = getNode(4); head->next->next->next = getNode(5); cout << "Linked list before insertion: "; display(head); int x = 3; insertAtMid(&head, x); cout << "\nLinked list after insertion: "; display(head); return 0; } |
chevron_right
filter_none
Java
// Java implementation to insert node // at the middle of the linked list import java.util.*; import java.lang.*; import java.io.*; class LinkedList { static Node head; // head of list /* Node Class */ static class Node { int data; Node next; // Constructor to create a new node Node(int d) { data = d; next = null; } } // function to insert node at the // middle of the linked list static void insertAtMid(int x) { // if list is empty if (head == null) head = new Node(x); else { // get a new node Node newNode = new Node(x); // assign values to the slow // and fast pointers Node slow = head; Node fast = head.next; while (fast != null && fast.next != null) { // move slow pointer to next node slow = slow.next; // move fast pointer two nodes // at a time fast = fast.next.next; } // insert the 'newNode' and adjust // the required links newNode.next = slow.next; slow.next = newNode; } } // function to display the linked list static void display() { Node temp = head; while (temp != null) { System.out.print(temp.data + " "); temp = temp.next; } } // Driver program to test above public static void main (String[] args) { // Creating the list 1.2.4.5 head = null; head = new Node(1); head.next = new Node(2); head.next.next = new Node(4); head.next.next.next = new Node(5); System.out.println("Linked list before"+ " insertion: "); display(); int x = 3; insertAtMid(x); System.out.println("\nLinked list after"+ " insertion: "); display(); } } // This article is contributed by Chhavi |
chevron_right
filter_none
Python3
# Python implementation to insert node # at the middle of the linked list # Node Class class Node : def __init__(self, d): self.data = d self.next = None class LinkedList: # function to insert node at the # middle of the linked list def __init__(self): self.head = None # Function to insert a new node # at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node def insertAtMid(self, x): # if list is empty if (self.head == None): self.head = Node(x) else: # get a new node newNode = Node(x) # assign values to the slow # and fast pointers slow = self.head fast = self.head.next while (fast != None and fast.next != None): # move slow pointer to next node slow = slow.next # move fast pointer two nodes # at a time fast = fast.next.next # insert the 'newNode' and # adjust the required links newNode.next = slow.next slow.next = newNode # function to display the linked list def display(self): temp = self.head while (temp != None): print(temp.data, end = " "), temp = temp.next # Driver Code # Creating the list 1.2.4.5 ll = LinkedList() ll.push(5) ll.push(4) ll.push(2) ll.push(1) print("Linked list before insertion: "), ll.display() x = 3ll.insertAtMid(x) print("\nLinked list after insertion: "), ll.display() # This code is contributed by prerna saini |
chevron_right
filter_none
C#
// C# implementation to insert node // at the middle of the linked list using System; public class LinkedList { static Node head; // head of list /* Node Class */ class Node { public int data; public Node next; // Constructor to create a new node public Node(int d) { data = d; next = null; } } // function to insert node at the // middle of the linked list static void insertAtMid(int x) { // if list is empty if (head == null) head = new Node(x); else { // get a new node Node newNode = new Node(x); // assign values to the slow // and fast pointers Node slow = head; Node fast = head.next; while (fast != null && fast.next != null) { // move slow pointer to next node slow = slow.next; // move fast pointer two nodes // at a time fast = fast.next.next; } // insert the 'newNode' and adjust // the required links newNode.next = slow.next; slow.next = newNode; } } // function to display the linked list static void display() { Node temp = head; while (temp != null) { Console.Write(temp.data + " "); temp = temp.next; } } // Driver code public static void Main (String[] args) { // Creating the list 1.2.4.5 head = null; head = new Node(1); head.next = new Node(2); head.next.next = new Node(4); head.next.next.next = new Node(5); Console.WriteLine("Linked list before"+ " insertion: "); display(); int x = 3; insertAtMid(x); Console.WriteLine("\nLinked list after"+ " insertion: "); display(); } } // This code is contributed by Rajput-Ji |
chevron_right
filter_none
Output:
Linked list before insertion: 1 2 4 5 Linked list after insertion: 1 2 3 4 5
Time Complexity: O(n)
This article is contributed by Ayush Jauhari. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
Recommended Posts:
- Insert N elements in a Linked List one after other at middle position
- Find kth node from Middle towards Head of a Linked List
- Make middle node head in a linked list
- Insert a node at a specific position in a linked list
- Delete middle of linked list
- Find the middle of a given linked list in C and Java
- Find middle of singly linked list Recursively
- Create new linked list from two given linked list with greater element at each node
- Traverse Linked List from middle to left-right order using recursion
- Given a linked list of line segments, remove middle points
- Python program to find middle of a linked list using one traversal
- Insert a whole linked list into other at k-th position
- Iterative approach for removing middle points in a linked list of line segements
- Sorted insert for circular linked list
- Swap Kth node from beginning with Kth node from end in a Linked List
- Must Do Coding Questions for Companies like Amazon, Microsoft, Adobe, ...
- Find the winner of the Game to Win by erasing any two consecutive similar alphabets
- Find the integers that doesnot ends with T1 or T2 when squared and added X
- Program to Encrypt a String using ! and @
- Compare two strings considering only alphanumeric characters