# Inner reducing pattern printing

Given a number N, print the following pattern. Examples :

```Input : 4
Output : 4444444
4333334
4322234
4321234
4322234
4333334
4444444
Explanation:
(1) Given value of n forms the outer-most
rectangular box layer.
(2) Value of n reduces by 1 and forms an
inner rectangular box layer.
(3) The step (2) is repeated until n
reduces to 1.

Input : 3
Output : 33333
32223
32123
32223
33333```

## C++

 `// C++ Program to print rectangular` `// inner reducing pattern` `#include ` `using` `namespace` `std;`   `#define max 100`   `// function to Print pattern` `void` `print(``int` `a[][max], ``int` `size) ` `{` `for` `(``int` `i = 0; i < size; i++) {` `    ``for` `(``int` `j = 0; j < size; j++) {` `    ``cout << a[i][j];` `    ``}` `    ``cout << endl;` `}` `}`   `// function to compute pattern` `void` `innerPattern(``int` `n) {` `    `  `// Pattern Size` `int` `size = 2 * n - 1;` `int` `front = 0;` `int` `back = size - 1;` `int` `a[max][max];` `while` `(n != 0) ` `{` `    ``for` `(``int` `i = front; i <= back; i++) {` `    ``for` `(``int` `j = front; j <= back; j++) {` `        ``if` `(i == front || i == back ||` `            ``j == front || j == back)` `        ``a[i][j] = n;` `    ``}` `    ``}` `    ``++front;` `    ``--back;` `    ``--n;` `}` `print(a, size);` `}`   `// Driver code` `int` `main()` `{` `    ``// Input` `    ``int` `n = 4; ` `    `  `    ``// function calling` `    ``innerPattern(n);` `    `  `return` `0;` `}`   `// This code is contributed by Anant Agarwal.`

## Java

 `// Java Program to print rectangular` `// inner reducing pattern` `public` `class` `Pattern {` `    `  `    ``// function to compute pattern` `    ``public` `static` `void` `innerPattern(``int` `n)` `    ``{   ` `        ``// Pattern Size` `        ``int` `size = ``2` `* n - ``1``; ` `        ``int` `front = ``0``;` `        ``int` `back = size - ``1``;` `        ``int` `a[][] = ``new` `int``[size][size];` `        ``while` `(n != ``0``) {` `            ``for` `(``int` `i = front; i <= back; i++) {` `                ``for` `(``int` `j = front; j <= back;` `                                        ``j++) {` `                    ``if` `(i == front || i == back ||` `                         ``j == front || j == back)` `                        ``a[i][j] = n;` `                ``}` `            ``}` `            ``++front;` `            ``--back;` `            ``--n;` `        ``}` `        ``print(a, size);` `    ``}`   `    ``// function to Print pattern` `    ``public` `static` `void` `print(``int` `a[][], ``int` `size)` `    ``{` `        ``for` `(``int` `i = ``0``; i < size; i++) {` `            ``for` `(``int` `j = ``0``; j < size; j++) {` `                ``System.out.print(a[i][j]);` `            ``}` `            ``System.out.println();` `        ``}` `    ``}`   `    ``// Main Method` `    ``public` `static` `void` `main(String[] args)` `    ``{` `        ``int` `n = ``4``; ``// Input` `        ``innerPattern(n);` `    ``}` `}`

## Python3

 `# Python3 Program to print rectangular ` `# inner reducing pattern ` `MAX` `=` `100`   `# function to Print pattern ` `def` `prints(a, size): ` `    ``for` `i ``in` `range``(size): ` `        ``for` `j ``in` `range``(size):` `            ``print``(a[i][j], end ``=` `'')` `        ``print``()`   `# function to compute pattern ` `def` `innerPattern(n): ` `    `  `    ``# Pattern Size ` `    ``size ``=` `2` `*` `n ``-` `1` `    ``front ``=` `0` `    ``back ``=` `size ``-` `1` `    ``a ``=` `[[``0` `for` `i ``in` `range``(``MAX``)]  ` `            ``for` `i ``in` `range``(``MAX``)]` `    ``while` `(n !``=` `0``): ` `        ``for` `i ``in` `range``(front, back ``+` `1``):` `            ``for` `j ``in` `range``(front, back ``+` `1``):` `                ``if` `(i ``=``=` `front ``or` `i ``=``=` `back ``or` `                    ``j ``=``=` `front ``or` `j ``=``=` `back):` `                    ``a[i][j] ``=` `n` `        ``front ``+``=` `1` `        ``back ``-``=` `1` `        ``n ``-``=` `1` `    ``prints(a, size); `   `# Driver code `   `# Input ` `n ``=` `4`   `# function calling ` `innerPattern(n)`   `# This code is contributed ` `# by sahishelangia`

## C#

 `using` `System;`   `public` `class` `Pattern {` `  `  `  ``// function to compute pattern` `  ``public` `static` `void` `InnerPattern(``int` `n)` `  ``{` `    `  `    ``// Pattern Size` `    ``int` `size = 2 * n - 1;` `    ``int` `front = 0;` `    ``int` `back = size - 1;` `    ``int``[, ] a = ``new` `int``[size, size];`   `    ``while` `(n != 0) {` `      ``for` `(``int` `i = front; i <= back; i++) {` `        ``for` `(``int` `j = front; j <= back; j++) {` `          ``if` `(i == front || i == back` `              ``|| j == front || j == back)` `            ``a[i, j] = n;` `        ``}` `      ``}` `      ``++front;` `      ``--back;` `      ``--n;` `    ``}` `    ``Print(a, size);` `  ``}`   `  ``// function to Print pattern` `  ``public` `static` `void` `Print(``int``[, ] a, ``int` `size)` `  ``{` `    ``for` `(``int` `i = 0; i < size; i++) {` `      ``for` `(``int` `j = 0; j < size; j++) {` `        ``Console.Write(a[i, j]);` `      ``}` `      ``Console.WriteLine();` `    ``}` `  ``}`   `  ``// Main Method` `  ``public` `static` `void` `Main(``string``[] args)` `  ``{` `    ``int` `n = 4; ``// Input` `    ``InnerPattern(n);` `  ``}` `}`

## Javascript

 `const MAX = 100;`   `// function to Print pattern ` `function` `prints(a, size) {` `  ``for` `(let i = 0; i < size; i++) {` `    ``let row = ``''``;` `    ``for` `(let j = 0; j < size; j++) {` `      ``row += a[i][j];` `    ``}` `    ``console.log(row);` `  ``}` `}`   `// function to compute pattern ` `function` `innerPattern(n) {` `  ``// Pattern Size ` `  ``const size = 2 * n - 1;` `  ``let front = 0;` `  ``let back = size - 1;` `  ``let a = ``new` `Array(MAX).fill(0).map(() => ``new` `Array(MAX).fill(0));` `  ``while` `(n !== 0) {` `    ``for` `(let i = front; i <= back; i++) {` `      ``for` `(let j = front; j <= back; j++) {` `        ``if` `(i === front || i === back || j === front || j === back) {` `          ``a[i][j] = n;` `        ``}` `      ``}` `    ``}` `    ``front += 1;` `    ``back -= 1;` `    ``n -= 1;` `  ``}` `  ``prints(a, size);` `}`   `// Driver code `   `// Input ` `const n = 4;`   `// function calling ` `innerPattern(n);`

Output :

```4444444
4333334
4322234
4321234
4322234
4333334
4444444```

If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Previous
Next
Similar Reads
Complete Tutorials