In this article, a static map is created and initialised in Java using Double Brace Initialization.
Static Map in Java
A static map is a map which is defined as static. It means that the map becomes a class member and can be easily used using class.
Double Brace Initialization
In Double Brace Initialization:
- The first brace creates a new Anonymous Inner Class. These inner classes are capable of accessing the behaviour of their parent class. So, in our case, we are actually creating a subclass of HashMap class, so this inner class is capable of using put() method.
- The second braces are instance initializers. The code an instance initializers inside is executed whenever an instance is created.
Approach:
- Pass the map values as Key and Value pair in the Double braces.
- A static factory Map instance is returned.
- Store it in Map and use.
Below is the implementation of the above approach:
Example 1:
import java.util.*;
class GFG {
private static Map<String, String> map
= new HashMap<String, String>() {{
put( "1" , "GFG" );
put( "2" , "Geek" );
put( "3" , "GeeksForGeeks" );
}};
public static void main(String[] args)
{
System.out.println(map);
}
}
|
Output:
{1=GFG, 2=Geek, 3=GeeksForGeeks}
Example 2: To show with 10 key-value pairs
import java.util.*;
class GFG {
private static Map<String, String> map
= new HashMap<String, String>() {{
put( "1" , "GFG" );
put( "2" , "Geek" );
put( "3" , "GeeksForGeeks" );
put( "4" , "G" );
put( "5" , "e" );
put( "6" , "e" );
put( "7" , "k" );
put( "8" , "s" );
put( "9" , "f" );
put( "10" , "o" );
}};
public static void main(String[] args)
{
System.out.println(map);
}
}
|
Output:
{1=GFG, 2=Geek, 3=GeeksForGeeks, 4=G, 5=e, 6=e, 7=k, 8=s, 9=f, 10=o}
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