Initialize a list in a single line with a specified value using Java Stream
Given a value N, the task is to create a List having this value N in a single line in Java using Stream.
Examples:
Input: N = 5
Output: [5]
Input: N = GeeksForGeeks
Output: [GeeksForGeeks]
Approach:
- Get the value N
- Generate the Stream using generate() method
- Set the size of the List to be created as 1 using limit() method
- Pass the value to be mapped using map() method
- Convert the generated stream into List using Collectors.toList() and return it by collecting using collect() method
Below is the implementation of the above approach:
import java.io.*;
import java.util.*;
import java.util.stream.*;
class GFG {
public static <T> List<T> createList(T N)
{
int size = 1 ;
return Stream
.generate(String:: new )
.limit(size)
.map(s -> N)
.collect(Collectors.toList());
}
public static void main(String[] args)
{
int N = 1024 ;
System.out.println( "List with element "
+ N + ": "
+ createList(N));
String str = "GeeksForGeeks" ;
System.out.println( "List with element "
+ str + ": "
+ createList(str));
}
}
|
Output:
List with element 1024: [1024]
List with element GeeksForGeeks: [GeeksForGeeks]
Last Updated :
27 Dec, 2019
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