** Implicit Differentiation** is a useful tool in the arsenal of tools to tackle problems in

**and beyond which helps us differentiate the function without converting it into the explicit function of the independent variable. Suppose we don’t know the method of implicit differentiation. In that case, we have to convert each implicit function into an explicit function, which is sometimes very hard and sometimes it is not even possible.**

**calculus**Implicit differentiation makes these problems very easy to solve. In this article, we will learn all the necessary basics we need to know about** implicit differentiation formula, chain rule, implicit differentiation of inverse trigonometric functions, etc**.

**Table of Content**

## What is Implicit Differentiation?

** Implicit Differentiation** is the process of differentiation in which we differentiate the implicit function without converting it into an explicit function. For example, we need to find the slope of a circle with an origin at 0 and a radius r. Its equation is given as x

^{2}+ y

^{2}= r

^{2}.

Now, to find the slope we need to find the dy/dx of the given function, so without implicit differentiation, we have to convert this function into an explicit function i.e., **y = ∓√(r**^{2}** – x**^{2}** )** . The explicit function of this is comparatively hard to differentiate. Thus, we need to learn the implicit differentiation by which this can be very easily differentiated.

**Read More: ****Calculus in Maths**

**Prerequisite for Implicit Differentiation**

**Prerequisite for Implicit Differentiation**

There are some prerequisite concepts that we need to know before learning Implicit Differentiation, these prerequisites are as follows:

**Chain Rule **

**Chain Rule**

The chain rule is a formula to compute the derivative of a composite function. That is, if f and g are differentiable functions, then the chain rule expresses the derivative of their composite f ∘ g as f(g(x))’ = f'(g(x)) × g'(x)

**Implicit Function**

**Implicit Function**

When a function is not defined explicitly in terms of a single independent variable. Implicit Function is represented as f(x, y) = k, where k is a real number, then the function is called the implicit function. For example, y + x^{2 }= 5, x^{2} + y^{2} = r^{2}, etc.

**Explicit function**

**Explicit function**

When a function is defined in terms of a single independent variable explicitly such as y = f(x), then the function is called the explicit function. For example, y = x^{2}, y = 3x+7, y = sin x, etc.

** **f(x, y) = 0 e.g. y + x

^{2 }= 5

Here we took only 2 variables x and y to define the implicit function. But you can have any number of variables.Note:

## Chain Rule in Implicit Differentiation

The general chain rule that we follow in differentiation is also followed here. We represent the derivative of two functions in product form. This can be understood from the following example:

For example, we have to differentiate 3xy^{2} implicitly with respect to x.

d/dx(3xy) = 3y^{2}+3x.2ydy/dx.

## Implicit Differentiation Formula

In Implicit differentiation, we do the differentiation of functions expressed in terms of more than one variable. The formulas for derivatives of the functions are the same as normal differentiation but the derivative of another variable is done following chain rule. The general representation of implicit differentiation can be d/dx{f(x,y)}.

df/dx = (df/dy).(dy/dx)

## How to do Implicit Differentiation

The following steps need to be followed to differentiate any implicit function.

** Step 1:** Follow the rules of differentiation to differentiate both sides of the equation with respect to x.

** Step 2: **Use the chain rule to differentiate expressions involving y.

** Step 3: **Solve the equation for dy/dx.

**Example: Differentiate x**^{2}** + y**^{2}** = r**^{2}**.**

**Solution:**

Given equation:

x^{2}+ y^{2}= r^{2}

** Step 1: **Differentiate both sides wrt to x and follow the rules of differentiation.

d/dx{x

^{2 }+ y^{2}} = d/dx(r^{2})

** Step 2: **Using the chain rule

2x + 2y(dy/dx) = 0

** Step 3: **Simplify the equation

2y(dy/dx) = -2x

dy/dx = -x/y

Thus,** dy/dx = -x/y**

## Implicit Differentiation of Inverse Trigonometric Functions

Implicit differentiation is very useful in finding derivatives of Inverse trigonometric Functions.

Let us consider y = sin^{-1}(x) and we need to find its derivative,

Take sin both sides of the equation,

sin y = sin(sin^{-1}(x)

* ⇒ *sin y = x

Differentiating the above equation w.r.t x, we get

d/dx(sin y) = d/dx (x)

cos y(dy/dx) = 1

dy/dx = 1/(cos y)

Now, sin(y) = x

*⇒ x*^{2 }= sin^{2}(* y*)

*⇒ x*^{2 }+ *cos*^{2}(* y*) = 1

*⇒ cos*^{2}(* y*) = 1 – x

^{2}

* ⇒ cos*(

*) = *

*y*`\sqrt` `{1-x^2}` |

Substituting the value, we get

dy/dx = 1/(cos y)

dy/dx = 1/√(1 – x^{2})

## Difference between Implicit and Explicit Differentiation

Implicit Differentiation and Explicit Differentiation are the two methods of differentiation that are used in calculus. The differences between them are explained in the table below,

Implicit Differentiation | Explicit Differentiation |
---|---|

Used to find the derivative of a function that cannot be easily solved for y | Used to find the derivative of a function that can be easily solved for y |

Does not require the function to be expressed in terms of y | Requires the function to be expressed in terms of y |

Treats y as an implicit function of x | Treats y as an explicit function of x |

Involves taking the derivative of both sides of the equation with respect to x | Involves directly differentiating the function with respect to x |

Involves the chain rule and product rule to differentiate the function | Involves the power rule, product rule, quotient rule, and chain rule to differentiate the function |

Often used when solving equations that involve multiple variables or when finding higher-order derivatives | Often used when finding the slope of a tangent line or the instantaneous rate of change of a function |

** Read More**,

## Implicit Differentiation Examples

**Example 1: Find the derivative of y + x + 5 = 0.**

**Solution: **

Using Explicit Differentiation

+y+ 5 = 0x⇒ y = -(x + 5)

`\begin`

`{aligned}`

`\`

`\`

`\Rightarrow`

`\frac`

`{dy}{dx}&=-(1+0)`

`\`

`\`

`\Rightarrow`

`\frac`

`{dy}{dx}&=-1`

`\end`

`{aligned}`

Using Implicit Differentiationy + x + 5 = 0

Differentiating both sides wrt x

`\frac`

`{dy}{dx}+1+0=0`

Isolate dy/dx

`\frac`

`{dy}{dx}=-1`

**Example 2: Find the derivative of y**^{5 }**– y = x.**

**Solution: **

y

^{5 }– y = xDifferentiating the above equation with respect to x, we get

`\begin`

`{aligned} &`

`\Rightarrow`

`5y^4`

`\frac`

`{dy}{dx}-`

`\frac`

`{dy}{dx}&=1`

`\`

`\`

`&`

`\Rightarrow`

`(5y^4-1)`

`\frac`

`{dy}{dx}&=1`

`\`

`\`

`&`

`\Rightarrow`

`\frac`

`{dy}{dx}=`

`\frac`

`{1}{5y^4-1}`

`\end`

`{aligned}`

**Example 3: Find the derivative of 10x**^{4}** – 18xy**^{2}** + 10y**^{3}** = 48.**

**Solution: **

Given,

10x

^{4}– 18xy^{2}+ 10y^{3}= 48Differentiating both sides w.r.t x

`10(4x^3) − 18(x.2y`

`\frac`

`{dy}{dx} + y^2) + 10(3y^2`

`\frac`

`{dy}{dx}) = 0`

`40x^3 − 36xy`

`\frac`

`{dy}{dx} − 18y^2 + 30y^2`

`\frac`

`{dy}{dx} = 0`

Keeping all the terms involving dy/dx on left and rest terms on right side of equation

`−36xy`

`\frac`

`{dy}{dx} + 30y^2`

`\frac`

`{dy}{dx} = −40x^3+ 18y^2`

`(30y^2−36xy)`

`\frac`

`{dy}{dx}= 18y^2 − 40x^3`

Dividing both sides by 2

`(15y^2−18xy)`

`\frac`

`{dy}{dx}=9y^2 − 20x^3`

Finally Isolate dy/dx

`\bold`

`{`

`\frac`

`{dy}{dx}=`

`\frac`

`{9y^2 − 20x^3}{15y^2−18xy}}`

For the term xy

^{2 }we used the Product Rule: (f.g)’ = f.g’ + f’.g

`\begin`

`{aligned} (xy^2)’ &= x(y^2)’ + (x)’y^2`

`\`

`\`

`&=x({2y`

`\frac`

`{dy}{dx}})+y^2`

`\`

`\`

`&=2xy`

`\frac`

`{dy}{dx}+y^2`

`\end`

`{aligned}`

**Example 4: Find the derivative of x**^{4 }**+ 2y**^{2 }**= 8.**

**Solution: **

Given,

x

^{4 }+ 2y^{2 }= 8

`\begin`

`{aligned} 4x^3+4y`

`\frac`

`{dy}{dx}&=0`

`\`

`\`

`\frac`

`{dy}{dx}&=`

`\frac`

`{-x^3}{y}`

`\end`

`{aligned}`

## Practice Questions on Implicit Differentiation

**Q1: Differentiate 3x**^{2}** + y**^{3}** = 6x**

**Q2: Differentiate sin x = cos y**

**Q3: Find dy/dx if y**^{2}** + 2xy + x**^{3}** = 21**

**Q4: Find dy/dx if x**^{2}**/p**^{2}** + y**^{2}**/q**^{2}** = 2**

## Implicit Differentiation-FAQs

### 1. What is Implicit Differentiation?

Implicit differentiation is the process of differentiation of implictit function, where we differentiate the given implicit function without converting it into explicit fuction.

### 2. Why do we need Implicit Differentiation?

We need implicit differentiation, as not all implicit functions can be converted into explicit function and some which are possible to covert into explicit function are sometimes becomes very complicated and hard to calculate.

### 3. What is Implicit Differentiation Method?

Implicit differentiation is a method in calculus that is used to solve various problems of calculus. Implicit Differntiation is an application of Chain Rule.

### 4. What is the chain rule in Implicit Differentiation?

To differentiate a function f(g(x)), we use chain rule which states

d/dx(f(g(x))) = f'(g(x))×g'(x)Where ‘ represents the first-order derivative of the function.

### 5. Can Implicit Differentiation be used to find Higher-Order Derivatives?

Yes, implicit differentiation can be used to find higher-order derivatives. To find higher-order derivatives just differentiate the equation as many times as needed.

### 6. What is the Implicit Differentiation Formula?

The Implicit Differentiation Formula is,

.du/dx = du/dy.dy/dx

### 7. When Can Implicit Differntiation be Used?

Implicit functions are the function that have both dependent and independent variable multiplied with each other. These types of functions are differentiated using Implicit Differntiation method.