# Line slope calculator 3x-5y=7

**Straight line given by points A[4; 1] and B[9; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x-1.4

**Canonical form of the line equation:**3x-5y-7 = 0

**Parametric form of the line equation:**

x = 5t+4

y = 3t+1 ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= 2.3333

**Y intercept:**y

_{0}= q = -1.4

**Distance line from the origin:**d

_{0}= 1.2005

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[6.5; 2.5]

**Perpendicular Bisector equation:**5x+3y-40 = 0

**Vector OA = (4; 1) ; |OA| = 4.1231**

**Vector OB = (9; 4) ; |OB| = 9.8489**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 9°55'35″ = 0.1732 rad**