# Icositetragonal Number

Given a number N, the task is to find the Nth Icositetragonal number.

An Icositetragonal number is a class of figurate number. It has a 24-sided polygon called Icositetragon. The N-th Icositetragonal number count’s the number of dots and all others dots are surrounding with a common sharing corner and make a pattern.

Examples:

Input: N = 2
Output: 24

Input: N = 6
Output: 336

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The Nth icositetragonal number is given by the formula:

```
```

Below is the implementation of the above approach:

## C++

 `// C++ program to find nth ` `// Icositetragonal number ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to find ` `// Icositetragonal number ` `int` `Icositetragonal_num(``int` `n) ` `{ ` `    ``// Formula to calculate nth ` `    ``// Icositetragonal number ` `    ``return` `(22 * n * n - 20 * n) / 2; ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `n = 3; ` ` `  `    ``cout << Icositetragonal_num(n) << endl; ` ` `  `    ``n = 10; ` ` `  `    ``cout << Icositetragonal_num(n); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to find nth ` `// icositetragonal number ` `import` `java.util.*; ` ` `  `class` `GFG { ` `     `  `// Function to find ` `// icositetragonal number ` `static` `int` `Icositetragonal_num(``int` `n) ` `{ ` `     `  `    ``// Formula to calculate nth ` `    ``// icositetragonal number ` `    ``return` `(``22` `* n * n - ``20` `* n) / ``2``; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `n = ``3``; ` `    ``System.out.println(Icositetragonal_num(n)); ` `     `  `    ``n = ``10``; ` `    ``System.out.println(Icositetragonal_num(n)); ` `} ` `} ` ` `  `// This code is contributed by offbeat `

## Python3

 `# Python3 program to find nth  ` `# Icositetragonal number  ` ` `  `# Function to find ` `# Icositetragonal number ` `def` `Icositetragonal_num(n): ` `     `  `    ``# Formula to calculate nth  ` `    ``# Icositetragonal number  ` `    ``return` `(``22` `*` `n ``*` `n ``-` `20` `*` `n) ``/` `2` ` `  `# Driver Code ` `n ``=` `3` `print``(``int``(Icositetragonal_num(n)))  ` ` `  `n ``=` `10` `print``(``int``(Icositetragonal_num(n)))  ` ` `  `# This code is contributed by divyeshrabadiya07 `

## C#

 `// C# program to find nth ` `// icositetragonal number ` `using` `System; ` ` `  `class` `GFG{ ` `     `  `// Function to find ` `// icositetragonal number ` `static` `int` `Icositetragonal_num(``int` `n) ` `{ ` `     `  `    ``// Formula to calculate nth ` `    ``// icositetragonal number ` `    ``return` `(22 * n * n - 20 * n) / 2; ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main(``string``[] args) ` `{ ` `    ``int` `n = 3; ` `    ``Console.Write(Icositetragonal_num(n) + ``"\n"``); ` `     `  `    ``n = 10; ` `    ``Console.Write(Icositetragonal_num(n) + ``"\n"``); ` `} ` `} ` ` `  `// This code is contributed by rutvik_56 `

Output:

```69
1000
```

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