# Icosihexagonal Number

Given a number N, the task is to find Nth Icosihexagon number.

An Icosihexagon number is class of figurate number. It has 26 – sided polygon called Icosihexagon. The N-th Icosihexagonal number count’s the 26 number of dots and all other dots are surrounding with a common sharing corner and make a pattern. The first few Icosihexagonol numbers are 1, 26, 75, 148 …

Examples:

Input: N = 2
Output: 26
Explanation:
The second Icosihexagonol number is 26.

Input: N = 3
Output: 75

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The N-th Icosihexagonal number is given by the formula:

• Nth term of s sided polygon =
• Therefore Nth term of 26 sided polygon is

Below is the implementation of the above approach:

## C++

 // C++ program for above approach  #include  using namespace std;     // Finding the nth Icosihexagonal Number  int IcosihexagonalNum(int n)  {      return (24 * n * n - 22 * n) / 2;  }     // Driver Code  int main()  {      int n = 3;      cout << "3rd Icosihexagonal Number is = "          << IcosihexagonalNum(n);         return 0;  }     // This code is contributed by Code_Mech

## C

 // C program for above approach  #include  #include     // Finding the nth Icosihexagonal Number  int IcosihexagonalNum(int n)  {      return (24 * n * n - 22 * n) / 2;  }     // Driver program to test above function  int main()  {      int n = 3;      printf("3rd Icosihexagonal Number is = %d",             IcosihexagonalNum(n));         return 0;  }

## Java

 // Java program for above approach   class GFG{         // Finding the nth icosihexagonal number   public static int IcosihexagonalNum(int n)   {       return (24 * n * n - 22 * n) / 2;   }      // Driver code  public static void main(String[] args)  {      int n = 3;              System.out.println("3rd Icosihexagonal Number is = " +                                       IcosihexagonalNum(n));  }  }     // This code is contributed by divyeshrabadiya07

## Python3

 # Python3 program for above approach      # Finding the nth Icosihexagonal Number   def IcosihexagonalNum(n):          return (24 * n * n - 22 * n) // 2    # Driver Code  n = 3 print("3rd Icosihexagonal Number is = ",                      IcosihexagonalNum(n))      # This code is contributed by divyamohan123

## C#

 // C# program for above approach   using System;     class GFG{         // Finding the nth icosihexagonal number   public static int IcosihexagonalNum(int n)   {       return (24 * n * n - 22 * n) / 2;   }      // Driver code  public static void Main(String[] args)  {      int n = 3;              Console.WriteLine("3rd Icosihexagonal Number is = " +                                      IcosihexagonalNum(n));  }  }     // This code is contributed by 29AjayKumar

Output:

3rd Icosihexagonal Number is = 75


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