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1x^2+5x-1=2

We move all terms to the left:

1x^2+5x-1-(2)=0

We add all the numbers together, and all the variables

x^2+5x-3=0

a = 1; b = 5; c = -3;

Δ = b^{2}-4ac

Δ = 5^{2}-4·1·(-3)

Δ = 37

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{37}}{2*1}=\frac{-5-\sqrt{37}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{37}}{2*1}=\frac{-5+\sqrt{37}}{2} $

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