# How to validate Indian driving license number using Regular Expression

Last Updated : 23 Dec, 2022

Given string str, the task is to check whether the given string is a valid Indian driving license number or not by using Regular Expression.
The valid Indian driving license number must satisfy the following conditions:

1. It should be 16 characters long (including space or hyphen (-)).
2. The driving license number can be entered in any of the following formats:
```HR-0619850034761
OR
HR06 19850034761```
1. The first two characters should be upper-case alphabets that represent the state code.
2. The next two characters should be digits that represent the RTO code.
3. The next four characters should be digits that represent the license issued in a year.
4. The next seven characters should be any digits from 0-9.

Note: In this article, we will check the license issued year from 1900-2099. It can be customized to change the license issued year.

Examples:

Input: str = “HR-0619850034761”;
Output: true
Explanation:
The given string satisfies all the above mentioned conditions. Therefore, it is not a valid Indian driving license number.

Input: str = “MH27 30120034761”;
Output: false
Explanation:
The given string has the license issued year 3012, that is not a valid year because in this article we validate the year from 1900-2099. Therefore, it is not a valid Indian driving license number.

Input: str = “GJ-2420180”;
Output: false
Explanation:
The given string has 10 characters. Therefore, it is not a valid Indian driving license number.

Approach: The idea is to use Regular Expression to solve this problem. The following steps can be followed to compute the answer:

• Get the String.
• Create a regular expression to check valid Indian driving license numbers as mentioned below:

regex = “^(([A-Z]{2}[0-9]{2})( )|([A-Z]{2}-[0-9]{2}))((19|20)[0-9][0-9])[0-9]{7}\$”;

• Where:
• ^ represents the starting of the string.
• ( represents the starting of group 1.
• ( represents the starting of group 2.
• [A-Z]{2} represents the first two characters should be upper case alphabets.
• [0-9]{2} represents the next two characters should be digits.
• ) represents the ending of group 2.
• ( ) represents the white space character.
• | represents the or.
• ( represents the starting of group 3.
• [A-Z]{2} represents the first two characters should be upper case alphabets.
• represents the hyphen.
• [0-9]{2} represents the next two characters should be digits.
• ) represents the ending of the group 3.
• ) represents the ending of the group 1.
• ((19|20)[0-9][0-9]) represents the year from 1900-2099.
• [0-9]{7} represents the next seven characters should be any digits from 0-9.
• \$ represents the ending of the string.
• Match the given string with the Regular Expression, In Java, this can be done by using Pattern.matcher().
• Return true if the string matches with the given regular expression, else return false.

Below is the implementation of the above approach:

## C++

 `// C++ program to validate the` `// Indian driving license number` `// using Regular Expression` `#include ` `#include ` `using` `namespace` `std;`   `// Function to validate the ` `// Indian driving license number` `bool` `isValidLicenseNo(string str)` `{`   `    ``// Regex to check valid ` `    ``// Indian driving license number` `    ``const` `regex pattern(``"^(([A-Z]{2}[0-9]{2})( "` `                        ``")|([A-Z]{2}-[0-9]{2}))"` `                        ``"((19|20)[0-"` `                        ``"9][0-9])[0-9]{7}\$"``);`   `    ``// If the Indian driving ` `    ``// license number is empty return false` `    ``if` `(str.empty()) ` `    ``{` `        ``return` `false``;` `    ``}`   `    ``// Return true if the Indian ` `    ``// driving license number ` `    ``// matched the ReGex` `    ``if` `(regex_match(str, pattern)) ` `    ``{` `        ``return` `true``;` `    ``}` `    ``else` `{` `        ``return` `false``;` `    ``}` `}`   `// Driver Code` `int` `main()` `{` `    ``// Test Case 1:` `    ``string str1 = ``"HR-0619850034761"``;` `    ``cout << isValidLicenseNo(str1) << endl;`   `    ``// Test Case 2:` `    ``string str2 = ``"UP14 20160034761"``;` `    ``cout << isValidLicenseNo(str2) << endl;`   `    ``// Test Case 3:` `    ``string str3 = ``"12HR-37200602347"``;` `    ``cout << isValidLicenseNo(str3) << endl;`   `    ``// Test Case 4:` `    ``string str4 = ``"MH27 30123476102"``;` `    ``cout << isValidLicenseNo(str4) << endl;`   `    ``// Test Case 5:` `    ``string str5 = ``"GJ-2420180"``;` `    ``cout << isValidLicenseNo(str5) << endl;`   `    ``return` `0;` `}`   `// This code is contributed by yuvraj_chandra`

## Java

 `// Java program to validate` `// Indian driving license number` `// using regular expression`   `import` `java.util.regex.*;` `class` `GFG {`   `    ``// Function to validate` `    ``// Indian driving license number` `    ``// using regular expression` `    ``public` `static` `boolean` `isValidLicenseNo(String str)` `    ``{` `        ``// Regex to check valid` `        ``// Indian driving license number` `        ``String regex = ``"^(([A-Z]{2}[0-9]{2})"` `                       ``+ ``"( )|([A-Z]{2}-[0-9]"` `                       ``+ ``"{2}))((19|20)[0-9]"` `                       ``+ ``"[0-9])[0-9]{7}\$"``;`   `        ``// Compile the ReGex` `        ``Pattern p = Pattern.compile(regex);`   `        ``// If the string is empty` `        ``// return false` `        ``if` `(str == ``null``) {` `            ``return` `false``;` `        ``}`   `        ``// Find match between given string` `        ``// and regular expression` `        ``// uSing Pattern.matcher()`   `        ``Matcher m = p.matcher(str);`   `        ``// Return if the string` `        ``// matched the ReGex` `        ``return` `m.matches();` `    ``}`   `    ``// Driver code` `    ``public` `static` `void` `main(String args[])` `    ``{`   `        ``// Test Case 1:` `        ``String str1 = ``"HR-0619850034761"``;` `        ``System.out.println(isValidLicenseNo(str1));`   `        ``// Test Case 2:` `        ``String str2 = ``"UP14 20160034761"``;` `        ``System.out.println(isValidLicenseNo(str2));`   `        ``// Test Case 3:` `        ``String str3 = ``"12HR-37200602347"``;` `        ``System.out.println(isValidLicenseNo(str3));`   `        ``// Test Case 4:` `        ``String str4 = ``"MH27 30123476102"``;` `        ``System.out.println(isValidLicenseNo(str4));`   `        ``// Test Case 5:` `        ``String str5 = ``"GJ-2420180"``;` `        ``System.out.println(isValidLicenseNo(str5));` `    ``}` `}`

## Python3

 `# Python program to validate ` `# Indian driving license number ` `# using regular expression`   `import` `re`   `# Function to validate Indian ` `# driving license number. ` `def` `isValidLicenseNo(``str``):`   `    ``# Regex to check valid ` `    ``# Indian driving license number ` `    ``regex ``=` `(``"^(([A-Z]{2}[0-9]{2})"` `+` `             ``"( )|([A-Z]{2}-[0-9]"` `+` `             ``"{2}))((19|20)[0-9]"` `+` `             ``"[0-9])[0-9]{7}\$"``)` `    `  `    ``# Compile the ReGex` `    ``p ``=` `re.``compile``(regex)`   `    ``# If the string is empty ` `    ``# return false` `    ``if` `(``str` `=``=` `None``):` `        ``return` `False`   `    ``# Return if the string ` `    ``# matched the ReGex` `    ``if``(re.search(p, ``str``)):` `        ``return` `True` `    ``else``:` `        ``return` `False`   `# Driver code`   `# Test Case 1:` `str1 ``=` `"HR-0619850034761"` `print``(isValidLicenseNo(str1))`   `# Test Case 2:` `str2 ``=` `"UP14 20160034761"` `print``(isValidLicenseNo(str2))`   `# Test Case 3:` `str3 ``=` `"12HR-37200602347"` `print``(isValidLicenseNo(str3))`   `# Test Case 4:` `str4 ``=` `"MH27 30123476102"` `print``(isValidLicenseNo(str4))`   `# Test Case 5:` `str5 ``=` `"GJ-2420180"` `print``(isValidLicenseNo(str5))`   `# This code is contributed by avanitrachhadiya2155`

## C#

 `// C# program to validate` `// Indian driving license number` `// using regular expression` `using` `System;` `using` `System.Text.RegularExpressions;`   `class` `GFG {`   `  ``// Function to validate` `  ``// Indian driving license number` `  ``// using regular expression` `  ``public` `static` `bool` `isValidLicenseNo(``string` `str)` `  ``{` `    ``// Regex to check valid` `    ``// Indian driving license number` `    ``string` `regex = ``"^(([A-Z]{2}[0-9]{2})"` `      ``+ ``"( )|([A-Z]{2}-[0-9]"` `      ``+ ``"{2}))((19|20)[0-9]"` `      ``+ ``"[0-9])[0-9]{7}\$"``;`   `    ``// Compile the ReGex` `    ``Regex p = ``new` `Regex(regex);`   `    ``// If the string is empty` `    ``// return false` `    ``if` `(str == ``null``) {` `      ``return` `false``;` `    ``}`   `    ``// Find match between given string` `    ``// and regular expression` `    ``// uSing Pattern.matcher()`   `    ``Match m = p.Match(str);`   `    ``// Return if the string` `    ``// matched the ReGex` `    ``return` `m.Success;` `  ``}`   `  ``// Driver code` `  ``public` `static` `void` `Main()` `  ``{`   `    ``// Test Case 1:` `    ``string` `str1 = ``"HR-0619850034761"``;` `    ``Console.WriteLine(isValidLicenseNo(str1));`   `    ``// Test Case 2:` `    ``string` `str2 = ``"UP14 20160034761"``;` `    ``Console.WriteLine(isValidLicenseNo(str2));`   `    ``// Test Case 3:` `    ``string` `str3 = ``"12HR-37200602347"``;` `    ``Console.WriteLine(isValidLicenseNo(str3));`   `    ``// Test Case 4:` `    ``string` `str4 = ``"MH27 30123476102"``;` `    ``Console.WriteLine(isValidLicenseNo(str4));`   `    ``// Test Case 5:` `    ``string` `str5 = ``"GJ-2420180"``;` `    ``Console.WriteLine(isValidLicenseNo(str5));` `  ``}` `}`   `// This code is contributed by Aman Kumar.`

## Javascript

 `// Javascript program to validate` `// License Number  using Regular Expression`   `// Function to validate the` `// license_Number  ` `function` `isValid_License_Number(license_Number)` `{` `    ``// Regex to check valid` `    ``// license_Number  ` `    ``let regex = ``new` `RegExp(/^(([A-Z]{2}[0-9]{2})( )|([A-Z]{2}-[0-9]{2}))((19|20)[0-9][0-9])[0-9]{7}\$/);`   `    ``// if license_Number ` `    ``// is empty return false` `    ``if` `(license_Number == ``null``) {` `        ``return` `"false"``;` `    ``}`   `    ``// Return true if the license_Number` `    ``// matched the ReGex` `    ``if` `(regex.test(license_Number) == ``true``) {` `        ``return` `"true"``;` `    ``}` `    ``else` `{` `        ``return` `"false"``;` `    ``}` `}`   `// Driver Code` `// Test Case 1:` `let str1 = ``"HR-0619850034761"``;` `console.log(isValid_License_Number(str1));`   `// Test Case 2:` `let str2 = ``"UP14 20160034761"``;` `console.log(isValid_License_Number(str2));`   `// Test Case 3:` `let str3 = ``"12HR-37200602347"``;` `console.log(isValid_License_Number(str3));`   `// Test Case 4:` `let str4 = ``"MH27 30123476102"``;` `console.log(isValid_License_Number(str4));`   `// Test Case 5:` `let str5 = ``"GJ-2420180"``;` `console.log(isValid_License_Number(str5));`   `// Test Case 6:` `let str6 = ``"RAH12071998"``;` `console.log(isValid_License_Number(str6));`   `// This code is contributed by Rahul Chauhan`

Output

```true
true
false
false
false```

Time Complexity: O(N) for each testcase, where N is the length of the given string.
Auxiliary Space: O(1)

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