# How to traverse a C++ set in reverse direction

• Last Updated : 07 Aug, 2022

Given a Set, the task is to traverse this Set in reverse order. Examples:

```Input: set = [10 20 30 70 80 90 100 40 50 60]
Output: 100 90 80 70 60 50 40 30 20 10

Input: set = [1 2 3 4 5]
Output: 5 4 3 2 1```

Approach: To traverse a Set in reverse order, a reverse_iterator can be declared on it and it can be used to traverse the set from the last element to the first element with the help of rbegin() and rend() functions.

1. Get the set.
2. Declare the reverse iterator on this set.
3. Traverse the set from the last element to the first element with the help of rbegin() and rend() functions.

Below is the implementation of the above approach: Program:

## CPP

 `#include ``using` `namespace` `std;` `int` `main()``{` `    ``// Get the set``    ``int` `arr[] = { 14, 12, 15, 11, 10 };` `    ``// initializes the set from an array``    ``set<``int``> s(arr, arr + ``sizeof``(arr) / ``sizeof``(arr[0]));` `    ``// declare iterator on set``    ``set<``int``>::iterator it;` `    ``cout << ``"Elements of Set in normal order:\n"``;` `    ``// prints all elements in normal order``    ``// using begin() and end() methods``    ``for` `(it = s.begin(); it != s.end(); it++)``        ``cout << *it << ``" "``;` `    ``// declare reverse_iterator on set``    ``set<``int``>::reverse_iterator rit;` `    ``cout << ``"\nElements of Set in reverse order:\n"``;` `    ``// prints all elements in reverse order``    ``// using rbegin() and rend() methods``    ``for` `(rit = s.rbegin(); rit != s.rend(); rit++)``        ``cout << *rit << ``" "``;` `    ``return` `0;``}`

Output:

```Elements of Set in normal order:
10 11 12 14 15
Elements of Set in reverse order:
15 14 12 11 10```

Time complexity: O(n) where n is no of elements in the given set

Auxiliary Space: O(n)

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