How to subtract one polynomial to another using NumPy in Python?
Last Updated :
29 Aug, 2020
In this article, let’s discuss how to subtract one polynomial to another. Two polynomials are given as input and the result is the subtraction of two polynomials.
- The polynomial p(x) = C3 x2 + C2 x + C1 is represented in NumPy as : ( C1, C2, C3 ) { the coefficients (constants)}.
- Let take two polynomials p(x) and q(x) then subtract these to get r(x) = p(x) – q(x) as a result of subtraction of two input polynomials.
If p(x) = A3 x2 + A2 x + A1
and
q(x) = B3 x2 + B2 x + B1
then result is
r(x) = p(x) - q(x) i.e;
r(x) = (A3 - B3) x2 + (A2 - B2) x + (A1 - B1)
and output is
( (A1 - B1), (A2 - B2), (A3 - B3) ).
In NumPy, it can be solved using the polysub() method. This function helps to find the difference of two polynomials and then returning the result as a polynomial
Below is the implementation with some examples :
Example 1: Using polysub()
Python3
import numpy
px = ( 5 , - 2 , 5 )
qx = ( 2 , - 5 , 2 )
rx = numpy.polynomial.polynomial.polysub(px,qx)
print (rx)
|
Output :
[ 3. 3. 3.]
Example 2: sub_with_decimals
Python3
import numpy
px = ( 0 , 0 , 2.2 )
qx = ( 9.8 , 0 , 4 )
rx = numpy.polynomial.polynomial.polysub(px,qx)
print (rx)
|
Output :
[-9.8 0. -1.8]
Example 3: #eval_then_sub
Python3
import numpy
px = ( 0 , 5 / 3 , 0 )
qx = ( - 7 / 4 , 0 , 9 / 5 )
rx = numpy.polynomial.polynomial.polysub(px,qx)
print (rx)
|
Output :
[ 1.75 1.66666667 -1.8 ]
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