How to sort an array of object by two fields in JavaScript ?
Last Updated :
13 Jul, 2023
We have given an array of objects and the task is to sort the array of elements by 2 fields of the object. There are two methods to solve this problem which are discussed below:
Approach 1:
- First compare the first property, if both are unequal then sort accordingly.
- If they are equal then do the same for the second property.
Example: This example implements the above approach with a custom comparison function.
Javascript
let arr = [
{ first: 3, second: 4 },
{ first: 3, second: 1 },
{ first: 1, second: 10 }
];
arr.sort( function (a, b) {
let af = a.first;
let bf = b.first;
let as = a.second;
let bs = b.second;
if (af == bf) {
return (as < bs) ? -1 : (as > bs) ? 1 : 0;
} else {
return (af < bf) ? -1 : 1;
}
});
console.log( "'" + JSON.stringify(arr[0])
+ ", " + JSON.stringify(arr[1]) + ", "
+ JSON.stringify(arr[2]) + "'" );
|
Output
'{"first":1,"second":10}, {"first":3,"second":1}, {"first":3,"second":4}'
Approach 2:
- First compare the first property, If both are unequal then sort accordingly.
- If they are equal then do the same for the second property, this example is following the same approach but uses OR Gate to reduce the code.
Example: This example implements the above approach with a custom comparison function.
Javascript
let arr = [
{ first: 3, second: 4 },
{ first: 3, second: 1 },
{ first: 1, second: 10 }
];
arr.sort( function (a, b) {
return a.first - b.first || a.second - b.second;
});
console.log( "'" + JSON.stringify(arr[0])
+ ", " + JSON.stringify(arr[1]) + ", "
+ JSON.stringify(arr[2]) + "'" );
|
Output
'{"first":1,"second":10}, {"first":3,"second":1}, {"first":3,"second":4}'
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