How to sort an Array in descending order using STL in C++?
Given an array arr[], sort this array in descending order using STL in C++.
Example:
Input: arr[] = {1, 45, 54, 71, 76, 12}
Output: {76, 71, 54, 45, 12, 1}
Input: arr[] = {1, 7, 5, 4, 6, 12}
Output: {12, 7, 6, 5, 4, 1}
Approach: Sorting can be done with the help of sort() function provided in STL.
Syntax:
sort(arr, arr + n, greater<T>());
// C++ program to sort Array // in descending order // using sort() in STL #include <bits/stdc++.h> using namespace std; int main() { // Get the array int arr[] = { 1, 45, 54, 71, 76, 12 }; // Compute the sizes int n = sizeof(arr) / sizeof(arr[0]); // Print the array cout << "Array: "; for (int i = 0; i < n; i++) cout << arr[i] << " "; // Sort the array in descending order sort(arr, arr + n, greater<int>()); // Print the sorted array cout << "\nDescending Sorted Array:\n"; for (int i = 0; i < n; i++) cout << arr[i] << " "; return 0; } |
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Output:
Array: 1 45 54 71 76 12 Descending Sorted Array: 76 71 54 45 12 1
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