How to sort an Array in descending order using STL in C++?

Given an array arr[], sort this array in descending order using STL in C++. Example:

Input: arr[] = {1, 45, 54, 71, 76, 12}
Output: {76, 71, 54, 45, 12, 1}

Input: arr[] = {1, 7, 5, 4, 6, 12}
Output: {12, 7, 6, 5, 4, 1}

Approach: Sorting can be done with the help of sort() function provided in STL. Syntax:

sort(arr, arr + n, greater<T>());

CPP

// C++ program to sort Array
// in descending order
// using sort() in STL

#include <bits/stdc++.h>
using namespace std;

int main()
{
    // Get the array
    int arr[] = { 1, 45, 54, 71, 76, 12 };

    // Compute the sizes
    int n = sizeof(arr) / sizeof(arr[0]);

    // Print the array
    cout << "Array: ";
    for (int i = 0; i < n; i++)
        cout << arr[i] << " ";

    // Sort the array in descending order
    sort(arr, arr + n, greater<int>());

    // Print the sorted array
    cout << "\nDescending Sorted Array:\n";
    for (int i = 0; i < n; i++)
        cout << arr[i] << " ";
    return 0;
}

Output:

Array: 1 45 54 71 76 12 
Descending Sorted Array:
76 71 54 45 12 1

Time Complexity: O(Nlog(N)) where N is the size of the array.
Auxiliary Space: O(1)

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