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# How to sort an Array in descending order using STL in C++?

• Difficulty Level : Medium
• Last Updated : 19 Mar, 2019

Given an array arr[], sort this array in descending order using STL in C++.

Example:

```Input: arr[] = {1, 45, 54, 71, 76, 12}
Output: {76, 71, 54, 45, 12, 1}

Input: arr[] = {1, 7, 5, 4, 6, 12}
Output: {12, 7, 6, 5, 4, 1}
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Sorting can be done with the help of sort() function provided in STL.

Syntax:

```sort(arr, arr + n, greater<T>());
```
 `// C++ program to sort Array``// in descending order``// using sort() in STL`` ` `#include ``using` `namespace` `std;`` ` `int` `main()``{``    ``// Get the array``    ``int` `arr[] = { 1, 45, 54, 71, 76, 12 };`` ` `    ``// Compute the sizes``    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr);`` ` `    ``// Print the array``    ``cout << ``"Array: "``;``    ``for` `(``int` `i = 0; i < n; i++)``        ``cout << arr[i] << ``" "``;`` ` `    ``// Sort the array in descending order``    ``sort(arr, arr + n, greater<``int``>());`` ` `    ``// Print the sorted array``    ``cout << ``"\nDescending Sorted Array:\n"``;``    ``for` `(``int` `i = 0; i < n; i++)``        ``cout << arr[i] << ``" "``;``    ``return` `0;``}`
Output:
```Array: 1 45 54 71 76 12
Descending Sorted Array:
76 71 54 45 12 1
```
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