How to Get Random Permutation of Integers in Golang?
Last Updated :
26 Mar, 2020
Go language provides inbuilt support for generating random numbers of the specified type with the help of a math/rand package. This package implements pseudo-random number generators. These random numbers are generated by a source and this source produces a deterministic sequence of values whenever the program run. And if you want to random numbers for security-sensitive work, then use the crypto/rand package.
You are allowed to generate a slice of n ints which contains a non-negative pseudo-random permutation of the integers [0, n) from the default source with the help of the Perm() Function provided by the math/rand package. So, you need to add a math/rand package in your program with the help of the import keyword to access the Perm() function.
Syntax:
func Perm(n int) []int
Let us discuss this concept with the help of the given examples:
Example 1:
package main
import (
"fmt"
"math/rand"
)
func main() {
for _, res_1 := range rand .Perm(4) {
fmt.Println( "Slice 1 Element: " , res_1)
}
for _, res_2 := range rand .Perm(3) {
fmt.Println( "Slice 2 Element: " , res_2)
}
}
|
Output:
Slice 1 Element: 0
Slice 1 Element: 1
Slice 1 Element: 2
Slice 1 Element: 3
Slice 2 Element: 1
Slice 2 Element: 2
Slice 2 Element: 0
Example 2:
package main
import (
"fmt"
"math/rand"
)
func main() {
res_1 := rand .Perm(5)
res_2 := rand .Perm(7)
fmt.Println( "Slice 1: " , res_1)
fmt.Println( "Length of Slice 1: " , len(res_1))
fmt.Println( "Capacity of Slice 1: " , cap(res_1))
fmt.Println( "Slice 2: " , res_2)
fmt.Println( "Length of Slice 2: " , len(res_2))
fmt.Println( "Capacity of Slice 2: " , cap(res_2))
}
|
Output:
Slice 1: [0 4 2 3 1]
Length of Slice 1: 5
Capacity of Slice 1: 5
Slice 2: [4 1 5 0 3 2 6]
Length of Slice 2: 7
Capacity of Slice 2: 7
Like Article
Suggest improvement
Share your thoughts in the comments
Please Login to comment...