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How to Get Intn Type Random Number in Golang?

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  • Last Updated : 01 Apr, 2020

Go language provides inbuilt support for generating random numbers of the specified type with the help of a math/rand package. This package implements pseudo-random number generators. These random numbers are generated by a source and this source produces a deterministic sequence of values every time when the program run. And if you want to random numbers for security-sensitive work, then use the crypto/rand package.

You are allowed to generate a non-negative pseudo-random number in [0, n) of int type from the default source with the help of the Intn() function provided by the math/rand package. So, you need to add a math/rand package in your program with the help of the import keyword to access Intn() function. This method will panic if the value of n is <= 0.


func Intn(n int) int

Let us discuss this concept with the help of the given examples:

Example 1:

// Golang program to illustrate
// how to Get Intn Type Random 
// Number
package main
import (
// Main function
func main() {
    // Finding random numbers of int type
    // Using Intn() function
    res_1 := rand.Intn(7)
    res_2 := rand.Intn(8)
    res_3 := rand.Intn(2)
    // Displaying the result
    fmt.Println("Random Number 1: ", res_1)
    fmt.Println("Random Number 2: ", res_2)
    fmt.Println("Random Number 3: ", res_3)


Random Number 1:  6
Random Number 2:  7
Random Number 3:  1

Example 2:

// Golang program to illustrate how 
// to get Intn Type Random Number
package main
import (
// Function
func intnrandom(value_1, value_2 int) int {
    return value_1 + value_2 + rand.Intn(4)
// Main function
func main() {
    // Getting result from Intnrandom() function
    res1 := intnrandom(10, 3)
    res2 := intnrandom(44, 59)
    res3 := intnrandom(130, 50)
    // Displaying results
    fmt.Println("Result 1: ", res1)
    fmt.Println("Result 2: ", res2)
    fmt.Println("Result 3: ", res3)


Result 1:  14
Result 2:  106
Result 3:  183

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