How to Get Int Type Random Number in Golang?
Go language provides inbuilt support for generating random numbers of the specified type with the help of a math/rand package. This package implements pseudo-random number generators. These random numbers are generated by a source and this source produces a deterministic sequence of values whenever the program run. And if you want to random numbers for security-sensitive work, then use the crypto/rand package.
You are allowed to generate a non-negative pseudo-random number of integer type from the default source with the help of the Int() function provided by the math/rand package. So, you need to add a math/rand package in your program with the help of the import keyword to access the Int() function.
Syntax:
func Int() int
Let us discuss this concept with the help of the given examples:
Example 1:
package main
import (
"fmt"
"math/rand"
)
func main() {
res_1 := rand .Int()
res_2 := rand .Int()
res_3 := rand .Int()
fmt.Println( "Random Number 1: " , res_1)
fmt.Println( "Random Number 2: " , res_2)
fmt.Println( "Random Number 3: " , res_3)
}
|
Output:
Random Number 1: 5577006791947779410
Random Number 2: 8674665223082153551
Random Number 3: 6129484611666145821
Example 2:
package main
import (
"fmt"
"math/rand"
)
func intrandom(value_1, value_2 int ) int {
return value_1 + value_2 + rand .Int()
}
func main() {
res1 := intrandom(2, 6)
res2 := intrandom(49, 50)
res3 := intrandom(120, 98)
fmt.Println( "Result 1: " , res1)
fmt.Println( "Result 2: " , res2)
fmt.Println( "Result 3: " , res3)
}
|
Output:
Result 1: 5577006791947779418
Result 2: 8674665223082153650
Result 3: 6129484611666146039
Last Updated :
26 Mar, 2020
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