 Open in App
Not now

# How to Count Variable Numbers of Arguments in C?

• Difficulty Level : Hard
• Last Updated : 28 May, 2017

C supports variable numbers of arguments. But there is no language provided way for finding out total number of arguments passed. User has to handle this in one of the following ways:
1) By passing first argument as count of arguments.
2) By passing last argument as NULL (or 0).
3) Using some printf (or scanf) like mechanism where first argument has placeholders for rest of the arguments.

Following is an example that uses first argument arg_count to hold count of other arguments.

 `#include ``#include `` ` `// this function returns minimum of integer numbers passed.  First ``// argument is count of numbers.``int` `min(``int` `arg_count, ...)``{``  ``int` `i;``  ``int` `min, a;``   ` `  ``// va_list is a type to hold information about variable arguments``  ``va_list` `ap; `` ` `  ``// va_start must be called before accessing variable argument list``  ``va_start``(ap, arg_count); ``    ` `  ``// Now arguments can be accessed one by one using va_arg macro``  ``// Initialize min as first argument in list   ``  ``min = ``va_arg``(ap, ``int``);``    ` `  ``// traverse rest of the arguments to find out minimum``  ``for``(i = 2; i <= arg_count; i++) {``    ``if``((a = ``va_arg``(ap, ``int``)) < min)``      ``min = a;``  ``}   `` ` `  ``//va_end should be executed before the function returns whenever``  ``// va_start has been previously used in that function ``  ``va_end``(ap);   `` ` `  ``return` `min;``}`` ` `int` `main()``{``   ``int` `count = 5;``    ` `   ``// Find minimum of 5 numbers: (12, 67, 6, 7, 100)``   ``printf``(``"Minimum value is %d"``, min(count, 12, 67, 6, 7, 100));``   ``getchar``();``   ``return` `0;``}`

Output:
Minimum value is 6