How to convert given number to a character array
Given an integer number N, the task is to convert it into a character array.
Example:
Input: N = 2020
Output: {2, 0, 2, 0}
Explanation: Here char array arr[] = {2, 0, 2, 0}
Input: N = 12349
Output: {1, 2, 3, 4, 9}
Explanation: Here char array arr[] = {1, 2, 3, 4, 9}
Approach: The basic approach to do this, is to recursively find all the digits of N, and insert it into the required character array.
- Count total digits in the number.
- Declare a char array of size digits in the number.
- Separating integer into digits and accommodate it to a character array.
- Add ASCII value of character ‘0’ is 48 in each element of the array.
Below is the implementation of the above approach:
C
// C program to convert integer// number into character array#include <stdio.h>#include <stdlib.h>// Function to convert integer to// character arraychar* convertIntegerToChar(int N){ // Count digits in number N int m = N; int digit = 0; while (m) { // Increment number of digits digit++; // Truncate the last // digit from the number m /= 10; } // Declare char array for result char* arr; // Declare duplicate char array char arr1[digit]; // Memory allocaton of array arr = (char*)malloc(digit); // Separating integer into digits and // accomodate it to character array int index = 0; while (N) { // Separate last digit from // the number and add ASCII // value of character '0' is 48 arr1[++index] = N % 10 + '0'; // Truncate the last // digit from the number N /= 10; } // Reverse the array for result int i; for (i = 0; i < index; i++) { arr[i] = arr1[index - i]; } // Char array truncate by null arr[i] = '\0'; // Return char array return (char*)arr;}// Driver Codeint main(){ // Given number int N = 12349; int len = 5; // Function call char* arr = convertIntegerToChar(N); // Print char array for (int i = 0; i < len; i++) printf("%c, ", arr[i]); return 0;} |
Java
// Java program to convert integer// number into character arrayclass GFG{ // Function to convert integer to// character arraystatic char[] convertIntegerToChar(int N){ // Count digits in number N int m = N; int digit = 0; while (m > 0) { // Increment number of digits digit++; // Truncate the last // digit from the number m /= 10; } // Declare char array for result char[] arr; // Declare duplicate char array char []arr1 = new char[digit + 1]; // Memory allocaton of array arr = new char[digit]; // Separating integer into digits and // accomodate it to character array int index = 0; while (N > 0) { // Separate last digit from // the number and add ASCII // value of character '0' is 48 arr1[++index] = (char)(N % 10 + '0'); // Truncate the last // digit from the number N /= 10; } // Reverse the array for result int i; for(i = 0; i < index; i++) { arr[i] = arr1[index - i]; } // Return char array return (char[])arr;}// Driver Codepublic static void main(String[] args){ // Given number int N = 12349; int len = 5; // Function call char[] arr = convertIntegerToChar(N); // Print char array for(int i = 0; i < len; i++) System.out.printf("%c, ", arr[i]);}}// This code is contributed by amal kumar choubey |
Python3
# Python3 program to convert integer# number into character array# Function to convert integer to# character arraydef convertIntegerToChar(N): # Count digits in number N m = N; digit = 0; while (m > 0): # Increment number of digits digit += 1; # Truncate the last # digit from the number m /= 10; # Declare char array for result arr = ['0' for i in range(digit)] # Declare duplicate char array arr1 = ['0' for i in range(digit + 1)]; # Separating integer # into digits and # accomodate it # to character array index = 0; while (N > 0): index += 1; # Separate last digit from # the number and add ASCII # value of character '0' is 48 arr1[index] = chr(int(N % 10 + 48)); # Truncate the last # digit from the number N = N // 10; # Reverse the array for result for i in range(0, index): arr[i] = arr1[index - i]; # Return char array return arr;# Driver Codeif __name__ == '__main__': # Given number N = 12349; len = 5; # Function call arr = convertIntegerToChar(N); # Print array for i in range(0, len, 1): print(arr[i], end = " ");# This code is contributed by gauravrajput1 |
C#
// C# program to convert integer// number into character arrayusing System;class GFG{ // Function to convert integer to// character arraystatic char[] convertintToChar(int N){ // Count digits in number N int m = N; int digit = 0; while (m > 0) { // Increment number of digits digit++; // Truncate the last // digit from the number m /= 10; } // Declare char array for result char[] arr; // Declare duplicate char array char []arr1 = new char[digit + 1]; // Memory allocaton of array arr = new char[digit]; // Separating integer into digits and // accomodate it to character array int index = 0; while (N > 0) { // Separate last digit from // the number and add ASCII // value of character '0' is 48 arr1[++index] = (char)(N % 10 + '0'); // Truncate the last // digit from the number N /= 10; } // Reverse the array for result int i; for(i = 0; i < index; i++) { arr[i] = arr1[index - i]; } // Return char array return (char[])arr;}// Driver Codepublic static void Main(String[] args){ // Given number int N = 12349; int len = 5; // Function call char[] arr = convertintToChar(N); // Print char array for(int i = 0; i < len; i++) Console.Write("{0}, ", arr[i]);}}// This code is contributed by amal kumar choubey |
Output:
1, 2, 3, 4, 9,
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