Given a string str, the task is to write a Java program to check whether a string contains only digits or not. If so, then print true, otherwise false.
Examples:

Input: str = “1234”
Output: true
Explanation:
The given string contains only digits so that output is true.

Input: str = “GeeksforGeeks2020”
Output: false
Explanation:
The given string contains alphabet character and digits so that output is false.

1. Using Traversal: The idea is to traverse each character in the string and check if the character of the string contains only digits from 0 to 9. If all the character of the string contains only digits then return true, otherwise, return false.

   Below is the implementation of the above approach:

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   // Java program for the above approach // contains only digits class GFG {        // Function to check if a string     // contains only digits     public static boolean     onlyDigits(String str, int n)     {         // Traverse the string from         // start to end         for (int i = 0; i < n; i++) {                // Check if character is             // digit from 0-9             // then return true             // else false             if (str.charAt(i) >= '0'                 && str.charAt(i) <= '9') {                 return true;             }             else {                 return false;             }         }         return false;     }        // Driver Code     public static void main(String args[])     {         // Given string str         String str = "1234";         int len = str.length();            // Function Call         System.out.println(onlyDigits(str, len));     } }

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   Output:

   
   

   
   

   true
   

   Time Complexity: O(N), where N is the length of the given string.
   Auxiliary Space: O(1)

2. Using Character.isDigit(char ch): The idea is to iterate over each character of the string and check whether the specified character is a digit or not using Character.isDigit(char ch). If the character is digit then return true, else return false.

   Below is the implementation of the above approach:

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   // Java program to check if a string // contains only digits class GFG {        // Function to check if a string     // contains only digits     public static boolean     onlyDigits(String str, int n)     {            // Traverse the string from         // start to end         for (int i = 0; i < n; i++) {                // Check if the sepecified             // character is a digit then             // return true,             // else return false             if (Character.isDigit(str.charAt(i))) {                 return true;             }             else {                 return false;             }         }         return false;     }        // Driver Code     public static void main(String args[])     {         // Given string str         String str = "1234";         int len = str.length();            // Function Call         System.out.println(onlyDigits(str, len));     } }

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   Output:

   true
   

   Time Complexity: O(N), where N is the length of the given string.
   Auxiliary Space: O(1)

3. Using Regular Expression:
   1. Get the String.
   2. Create a Regular Expression to check string contains only digits as mentioned below:

      regex = "[0-9]+";
      

   3. Match the given string with Regular Expression. In Java, this can be done by using Pattern.matcher().
   4. Return true if the string matches with the given regular expression, else return false.

   Below is the implementation of the above approach:

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   // Java program to check if a string // contains only digits import java.util.regex.*; class GFG {        // Function to validate URL     // using regular expression     public static boolean     onlyDigits(String str)     {         // Regex to check string         // contains only digits         String regex = "[0-9]+";            // Compile the ReGex         Pattern p = Pattern.compile(regex);            // If the string is empty         // return false         if (str == null) {             return false;         }            // Find match between given string         // and regular expression         // using Pattern.matcher()         Matcher m = p.matcher(str);            // Return if the string         // matched the ReGex         return m.matches();     }        // Driver Code     public static void main(String args[])     {         // Given string str         String str = "1234";            // Function Call         System.out.println(onlyDigits(str));     } }

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   Output:

   true
   

   Time Complexity: O(N), where N is the length of the given string.
   Auxiliary Space: O(1)

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