How to calculate log base 2 of an Integer in Java?
Given an integer N, the task is to calculate its log to the base 2, i.e. log2 N in Java.
Examples:
Input: N = 2
Output: 1
Input: 1024
Output: 10
Approach:
loga b = loge b / loge a
- Therefore we can calculate log2 N indirectly as:
log2 N = loge N / loge 2
Below is the implementation of the above approach:
Java
import java.io.*;
import java.lang.*;
class GFG {
public static int log2( int N)
{
int result = ( int )(Math.log(N) / Math.log( 2 ));
return result;
}
public static void main(String[] args)
{
int N = 1024 ;
System.out.println( "Log " + N + " to the base 2 = " + log2(N));
}
}
|
Output:
Log 1024 to the base 2 = 10
Last Updated :
11 Mar, 2022
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