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How to calculate Energy Density?

Last Updated : 22 Jun, 2022
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The calculation of the amount of energy that may be stored in a given mass of a substance or system is known as energy density. As a result, the higher the energy density of a system or material, the more energy is stored in its mass. Energy may be stored in a wide range of materials and methods. In four different types of reactions, any material can release energy. Nuclear, chemical, electrochemical, and electrical are the four types of energy. In most cases, only useable or extractable energy is assessed when estimating the quantity of energy in a system. 

Energy density 

Energy density is defined as the total amount of energy in a system per unit volume. For example, the number of calories per gram of food. Low-energy-density foods provide fewer calories per gram than high-energy-density foods, allowing you to consume more of them. It is symbolized by the letter U. Magnetic and electric fields can store energy.

Formula for energy density 

  • The energy density of a capacitor or electric field is represented as,

Electrical energy density =  permittivity × (Electric field)2 /2

UE = (1/2)ε0E2

Derivation of Electric field energy density 

Energy density = Energy/volume

UE = U/V

Energy (U) = 1/2 (ε0 × E2) × Ad

Volume(V) = Ad

UE = 1/2 (ε0 × E2) × Ad/Ad

UE = (1/2)ε0E2

  • For any inductor or magnetic field, electric density is represented as

Magnetic energy density = magnetic permeability × (magnetic field)2/2

UB = (1/2μ0)B2

Derivation of Magnetic field energy density 

Energy density = Energy/volume

UB = 1/2 (LI2)/Al

Flux = NBA = LI

B = μ0 NI/length

I = B (Length)/ Nμ0

UB = (1/2) (B (Length)/ Nμ0) (NBA)/A (length)

UB = (1/2μ0)B2

In the energy density of electromagnetic waves, both electric and magnetic fields contribute. Therefore total energy density is equal to the sum of the electric and magnetic fields. 

U = UE + UB

U = (1/2)ε0E2 + (1/2μ0)B2

Here, in the above-mentioned derivations the parameters are,

UE = Electrical Energy Density

UB = Magnetic Energy Density

ε0 = Permittivity,

μ0 = Permeability

E = Electric Field

B = Magnetic Field.

Sample Problems

Question 1: What is the energy density?

Answer:

Energy density is defined as the total amount of energy in a system per unit volume.

For the total energy density, the formula is given by U = (1/2)ε0E2 + (1/2)μ0B2

Question 2: What is the Formula for the energy density of an electric field or a capacitor?

Answer:

The energy density of an electric field or a capacitor is given by

UB = (1/2μ0)B2

Where,

UB = Magnetic Energy Density,
μ0 = Permeability
B = Magnetic Field.

Question 3: Calculate the energy density of a capacitor with an electric field of E = 15 V/m.

Solution:

Given: E = 15 V/m, ε0 = 8.8541 × 10-12 F/m

UE = (1/2)ε0E2

UE = (1/2) × 8.8541 × 10-12 × 225

UE = (1/2) × 1992.2× 10-12

UE = 996.1 × 10-12

UE = 9.96 × 10-10 FV2/m3

Question 4: Calculate the energy density of a capacitor with an electric field of E = 30 V/m.

Solution:

Given: E = 30 V/m, ε0 = 8.8541 × 10-12 F/m

UE = (1/2)ε0E2

UE = (1/2) × 8.8541 × 10-12 × (30)2

UE = (1/2) × 7968.69 × 10-12

UE = 3.984 × 10-9 FV2/m3

Question 5: If an inductor with a magnetic field of B = 6 T then calculate its energy density of it.

Solution:

Given: B = 6 T, μ0 = 4π × 10-7 NA-2

UB = (1/2μ0)B2

UB = (1/2 ×4π × 10-7)× 62

UB = (1/25.12 × 10-7) × 36

UB = 1.43 × 10-7 J/m3

Question 6: Calculate the energy density of both electric and magnetic fields, the magnetic field has a value of 2  Ã— 10-2 T and the electric field has a value of 4 × 107 V/m in a certain space of a region.

Solution:

Given: B = 2 × 10-2 T

E = 4 × 107 V/m

 Î¼0 = 4Ï€ × 10-7 NA-2

ε0 = 8.8541 × 10-12 F/m

Electrical energy density-

UE = (1/2) ε0E2

UE = 1/2 × 8.8541 × 10-12 × (4 × 107)2

UE = 7083.28 J/m3.

Magnetic energy density,

UB = (1/2 × μ0)B2

UB = (1/2 × 4π × 10-7) × (2 × 10-2)2

UB = 159.2 J/m3

Total energy density – U = UE +  UB

U = 7083.28 + 159.2

U = 7242.48 J/m3.


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