# How many words of 3 vowels and 6 consonants can be formed taken from 5 vowels and 10 consonants?

Permutation is known as the process of organizing the group, body, or numbers in order, selecting the body or numbers from the set, is known as combinations in such a way that the order of the number does not matter.

In mathematics, permutation is also known as the process of organizing a group in which all the members of a group are arranged into some sequence or order. The process of permuting is known as the repositioning of its components if the group is already arranged. Permutations take place, in almost every area of mathematics. They mostly appear when different commands on certain limited sets are considered.

**Permutation Formula**

In permutation r things are picked from a group of n things without any replacement. In this order of picking matter.

^{n}P_{r}= (n!)/(n – r)!Here,

n = group size, the total number of things in the group

r = subset size, the number of things to be selected from the group

**Combination**

A combination is a function of selecting the number from a set, such that (not like permutation) the order of choice doesn’t matter. In smaller cases, it is conceivable to count the number of combinations. The combination is known as the merging of n things taken k at a time without repetition. In combination, the order doesn’t matter you can select the items in any order. To those combinations in which re-occurrence is allowed, the terms k-selection or k-combination with replication are frequently used.

**Combination Formula**

In combination r things are picked from a set of n things and where the order of picking does not matter.

^{n}C_{r}= n!/((n-r)! r!)Here,

n = Number of items in set

r = Number of things picked from the group.

### How many words of 3 vowels and 6 consonants can be formed taken from 5 vowels and 10 consonants?

**Answer:**

Total no. of vowels = 5

Total no. of consonants = 10

No. of words with 3 vowels and 6 consonants

3 vowels can be selected from 5 vowels =

^{5}C_{3 }ways = n!/(n-r)!r!= 5!/(5-3)!3! =10 ways6 consonants can be selected from 10 consonants =

^{10}C_{6}ways = n!/(n-r)!r! = 10!/(10-6)!6! = 210 waysTotal selection =

^{5}C_{3 }×^{10}C_{6}Now, 9 letters in each selection can be arranged in 9! ways

Total no. of words =

^{5}C_{3 }×^{10}C_{6 }× 9!

_{ }= 10 × 210 × 9!= 2100 × 9!

= 762,048,000 words

**Similar Questions**

**Question 1: If 5 vowels and 6 consonants are given, then how many 6 letter words can be formed with 3 vowels and 3 consonants.**

**Answer:**

Total no. of vowels = 5

Total no. of consonants = 6

The no. of 6 letter words with 3 vowels and 3 consonants

3 vowels can be selected from 5 vowels =

^{5}C_{3}ways = n!/(n-r)!r!= 5!/(5-3)!3! =10 ways3 consonants can be selected from 6 consonants =

^{6}C_{3 }ways = n!/(n-r)!r! = 6!/(6-3)!3! = 20 waysTotal selection =

^{5}C_{3}×^{10}C_{6}Now, 6 letters in each selection can be arranged in 6! ways

Total no. of 6 letter words =

^{5}C_{3}×^{6}C_{3 }× 6!= 10 × 20 × 6!

= 200 × 6!

= 1,44,000 words

**Question 2: How many different words each containing 3 vowels and 5 consonants can be formed with 5 vowels and 19 consonants?**

**Answer:**

Total no. of vowels = 5

Total no. of consonants = 19

No. of words with 3 vowels and 5 consonants

3 vowels can be selected from 5 vowels =

^{5}C_{3}ways = n!/(n-r)!r!= 5!/(5-3)!3! =10 ways5 consonants can be selected from 19 consonants =

^{19}C_{5}ways = n!/(n-r)!r! = 19!/(19-5)!5! = 11,628 waysTotal selection =

^{5}C_{3}×^{19}C_{5}Now, 8 letters in each selection can be arranged in 8! ways

Total no. of words =

^{5}C_{3}×^{19}C_{5}× 8!= 10 × 11,628 × 8!

= 116280 × 8!

= 4,688,409,600 words

**Question 3: How many different words each containing 2 vowels and 3 consonants can be formed with 5 vowels and 17 consonants?**

**Answer:**

Total no. of vowels = 5

Total no. of consonants = 17

No. of different words with 2 vowels and 3 consonants

2 vowels can be selected from 5 vowels =

^{5}C_{2}ways = n!/(n-r)!r!= 5!/(5-2)!2! =10 ways3 consonants can be selected from 17 consonants =

^{17}C_{3}ways = n!/(n-r)!r! = 17!/(17-3)!3! = 680 waysTotal selection =

^{5}C_{2}×^{17}C_{3}Now, 5 letters in each selection can be arranged in 5! ways

Total no. of words =

^{5}C_{2}×^{17}C_{3}× 5!= 10 × 680 × 5!

= 6800 × 5!

= 8,16,000 words

**Question 4: How many different words each containing 2 vowels and 3 consonants can be formed with 4 vowels and 7 consonants?**

**Answer:**

Total no. of vowels = 4

Total no. of consonants = 7

No. of different words with 2 vowels and 3 consonants

2 vowels can be selected from 4 vowels =

^{4}C_{2}ways = n!/(n-r)!r!= 4!/(4-2)!2! = 6 ways3 consonants can be selected from 7 consonants =

^{7}C_{3}ways = n!/(n-r)!r! = 7!/(7-3)!3! = 35 waysTotal selection =

^{4}C_{2}×^{7}C_{3}Now, 5 letters in each selection can be arranged in 5! ways

Total no. of words =

^{4}C_{2 }×^{7}C_{3}× 5!= 6 × 35 × 5!

= 210 × 5!

= 25,200 words