Profile: Automation Testing/Manual Testing
Process: Written Test (90 Minutes) + 2 Technical Interviews.
Round 1 (Written Test)
It consists of 50 questions (including 2 programming questions, mandatory for Automation Testing). For Manual Testing, test case were to be written for an Instant Messaging app like hike/whatsapp.
Section 1- General Aptitude/Logical
Section 2- Software Knowledge (Questions like latest version of iOS, Windows, Android. Operating Systems etc)
Section 3- Database and Linux
Section 4- Computer Programming (Output questions of java/c/c++, generic questions related to programming)
Coding Question 1:
Given a string of parentheses, write a program to find whether its valid or not.
Examples-
input: {{{}}}
output: Valid
input: }{}{}{}}
output: Invalid
Coding Question 2:
Given ‘m’ number of small bricks (each x inches long) and ‘n’ big bricks (each y inches long), we want to create row which is z inches long using combination of small and big bricks. Write a program to verify whether it is possible to create such row of bricks or not.
Note: Solution Mx + Ny = z is not recommended.
Examples-
input: We have 4(m) small bricks each 3 inches(x) long and 3(n) big bricks each 4 inches(y) long. We need to create row which is 14(z) inches long.
output: Yes
input: We have 2(m) small bricks each 2 inches(x) long and 2(n) big bricks each 5 inches(y) long. We need to create row which is 6(z) inches long.
output: No (no combination of bricks will make wall which is 6 inches long).
Interview:
For automation testing- Programming question like
Convert a binary tree into its mirror.
Reversing a linked list.
Database Queries etc. were asked.
Solution Q1:
#include <stdio.h>
#include <stdlib.h>
int main()
{
char str[20];
int i=0;
printf("Enter String: ");
gets(str);
int count=0;
while (str[i]!='\0')
{
if (str[i]=='}')
count--;
if (str[i]=='{')
count++;
if (count<0)
{
break;
}
i++;
}
if (count==0)
printf("\nValid");
else
printf("\nInvalid");
return 0;
}
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Solution Q2:
#include <iostream>
using namespace std;
int main()
{
int m,x,n,y,z;
int small=0, large=0, sum=0;
cout << "Enter values : ";
cin >> m >> x >> n >> y >> z;
int i=0,j=0,flag=0;
for (i=0; i<m; i++)
{
small=small+x;
for (j=0; j<=n; j++)
{
sum=small+large;
if (sum>z)
break;
if (sum==z)
{
cout<<"\nYes. Combination Possible";
flag=1;
}
large=large+y;
}
large=0;
}
if (flag==0)
cout<<"\nNo. Not possible";
return 0;
}
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