HijrahDate isLeapYear() method in Java with Example
The isLeapYear() method of java.time.chrono.HijrahDate class is used to differentiate between the leap year and non leap year. If the year represented by this HijrahDate is a leap year, this method will return true, otherwise false.
Syntax:
public boolean isLeapYear()
Parameter: This method does not accept any argument as a parameter.
Return Value: This method returns Boolean value, i.e. true if the proleptic year is leap year otherwise false.
Below are the examples to illustrate the isLeapYear() method:
Example 1:
Java
import java.util.*;
import java.io.*;
import java.time.*;
import java.time.chrono.*;
public class GFG {
public static void main(String[] argv)
{
HijrahDate hidate
= HijrahDate.of( 1398 , 03 , 23 );
System.out.println( "HijrahDate: "
+ hidate.toString());
boolean flag = hidate.isLeapYear();
if (flag)
System.out.println( "Leap year" );
else
System.out.println( "Not a leap year" );
}
}
|
Output:
HijrahDate: Hijrah-umalqura AH 1398-03-23
Not a leap year
Example 2:
Java
import java.util.*;
import java.io.*;
import java.time.*;
import java.time.chrono.*;
public class GFG {
public static void main(String[] argv)
{
HijrahDate hidate = HijrahDate.now();
System.out.println( "HijrahDate: "
+ hidate.toString());
boolean flag = hidate.isLeapYear();
if (flag)
System.out.println( "Leap year" );
else
System.out.println( "Not a leap year" );
}
}
|
Output:
HijrahDate: Hijrah-umalqura AH 1441-06-25
Leap year
Reference: https://docs.oracle.com/javase/9/docs/api/java/time/chrono/HijrahDate.html#isLeapYear–
Last Updated :
27 Feb, 2020
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...