Related Articles
Highest power of 2 that divides a number represented in binary
• Difficulty Level : Medium
• Last Updated : 14 May, 2021

Given binary string str, the task is to find the largest power of 2 that divides the decimal equivalent of the given binary number.

Examples:

Input: str = “100100”
Output:
22 = 4 is the highest power of 2 that divides 36 (100100).
Input: str = “10010”
Output: 1

Approach: Starting from the right, count the number of 0s in the binary representation which is the highest power of 2 which will divide the number.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ``using` `namespace` `std;` `// Function to return the highest power of 2``// which divides the given binary number``int` `highestPower(string str, ``int` `len)``{` `    ``// To store the highest required power of 2``    ``int` `ans = 0;` `    ``// Counting number of consecutive zeros``    ``// from the end in the given binary string``    ``for` `(``int` `i = len - 1; i >= 0; i--) {``        ``if` `(str[i] == ``'0'``)``            ``ans++;``        ``else``            ``break``;``    ``}` `    ``return` `ans;``}` `// Driver code``int` `main()``{``    ``string str = ``"100100"``;``    ``int` `len = str.length();``    ``cout << highestPower(str, len);` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``class` `GFG``{``    ` `// Function to return the highest power of 2``// which divides the given binary number``static` `int` `highestPower(String str, ``int` `len)``{` `    ``// To store the highest required power of 2``    ``int` `ans = ``0``;` `    ``// Counting number of consecutive zeros``    ``// from the end in the given binary string``    ``for` `(``int` `i = len - ``1``; i >= ``0``; i--)``    ``{``        ``if` `(str.charAt(i) == ``'0'``)``            ``ans++;``        ``else``            ``break``;``    ``}` `    ``return` `ans;``}` `// Driver code``public` `static` `void` `main(String[] args)``{``    ``String str = ``"100100"``;``    ``int` `len = str.length();``    ``System.out.println(highestPower(str, len));``}``}` `// This code is contributed by Code_Mech.`

## Python3

 `# Python3 implementation of the approach` `# Function to return the highest power of 2``# which divides the given binary number``def` `highestPower(``str``, lenngth):` `    ``# To store the highest required power of 2``    ``ans ``=` `0``;` `    ``# Counting number of consecutive zeros``    ``# from the end in the given binary string``    ``for` `i ``in` `range``(lenngth``-``1``,``-``1``,``-``1``):``        ``if` `(``str``[i] ``=``=` `'0'``):``            ``ans``+``=``1``;``        ``else``:``            ``break``;``    ``return` `ans;` `# Driver code``def` `main():``    ``str` `=` `"100100"``;``    ``length ``=` `len``(``str``);``    ``print``(highestPower(``str``, length));` `if` `__name__ ``=``=` `'__main__'``:``    ``main()` `# This code contributed by PrinciRaj1992`

## C#

 `// C# implementation of the approach``using` `System;``    ` `class` `GFG``{``    ` `// Function to return the highest power of 2``// which divides the given binary number``static` `int` `highestPower(String str, ``int` `len)``{` `    ``// To store the highest required power of 2``    ``int` `ans = 0;` `    ``// Counting number of consecutive zeros``    ``// from the end in the given binary string``    ``for` `(``int` `i = len - 1; i >= 0; i--)``    ``{``        ``if` `(str[i] == ``'0'``)``            ``ans++;``        ``else``            ``break``;``    ``}` `    ``return` `ans;``}` `// Driver code``public` `static` `void` `Main(String[] args)``{``    ``String str = ``"100100"``;``    ``int` `len = str.Length;``    ``Console.WriteLine(highestPower(str, len));``}``}` `/* This code contributed by PrinciRaj1992 */`

## PHP

 `= 0; ``\$i``--)``    ``{``        ``if` `(``\$str``[``\$i``] == ``'0'``)``            ``\$ans``++;``        ``else``            ``break``;``    ``}` `    ``return` `\$ans``;``}` `// Driver code``\$str` `= ``"100100"``;``\$len` `= ``strlen``(``\$str``);``echo` `highestPower(``\$str``, ``\$len``);` `// This code is contributed by Ryuga``?>`

## Javascript

 ``
Output:
`2`

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with industry experts, please refer DSA Live Classes

My Personal Notes arrow_drop_up