Given a number **N**, the task is to find **N ^{th}** Hexacontagon number.

A Hexacontagon number is class of figurate number. It has 60 – sided polygon called hexacontagon. The N-th hexacontagon number count’s the 60 number of dots and all others dots are surrounding with a common sharing corner and make a pattern. The first few hexacontagonol numbers are

1, 60, 177, 352 …

**Examples:**

Input:N = 2

Output:60

Explanation:

The second hexacontagonol number is 60.

Input:N = 3

Output:177

**Approach:** The N-th hexacontagon number is given by the formula:

- Nth term of s sided polygon =
- Therefore Nth term of 60 sided polygon is

Below is the implementation of the above approach:

## C++

`// C++ program for above approach ` `#include <iostream> ` `using` `namespace` `std; ` ` ` `// Finding the nth hexacontagon number ` `int` `hexacontagonNum(` `int` `n) ` `{ ` ` ` `return` `(58 * n * n - 56 * n) / 2; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `int` `n = 3; ` ` ` `cout << ` `"3rd hexacontagon Number is = "` ` ` `<< hexacontagonNum(n); ` ` ` ` ` `return` `0; ` `} ` ` ` `// This code is contributed by shubhamsingh10 ` |

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## C

`// C program for above approach ` `#include <stdio.h> ` `#include <stdlib.h> ` ` ` `// Finding the nth hexacontagon Number ` `int` `hexacontagonNum(` `int` `n) ` `{ ` ` ` `return` `(58 * n * n - 56 * n) / 2; ` `} ` ` ` `// Driver program to test above function ` `int` `main() ` `{ ` ` ` `int` `n = 3; ` ` ` `printf` `(` `"3rd hexacontagon Number is = %d"` `, ` ` ` `hexacontagonNum(n)); ` ` ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program for above approach ` `class` `GFG{ ` ` ` `// Finding the nth hexacontagon number ` `public` `static` `int` `hexacontagonNum(` `int` `n) ` `{ ` ` ` `return` `(` `58` `* n * n - ` `56` `* n) / ` `2` `; ` `} ` ` ` `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` ` ` `int` `n = ` `3` `; ` ` ` `System.out.println(` `"3rd hexacontagon Number is = "` `+ ` ` ` `hexacontagonNum(n)); ` `} ` `} ` ` ` `// This code is contributed by divyeshrabadiya07 ` |

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## Python3

`# Python3 program for above approach ` ` ` `# Finding the nth hexacontagon Number ` `def` `hexacontagonNum(n): ` ` ` ` ` `return` `(` `58` `*` `n ` `*` `n ` `-` `56` `*` `n) ` `/` `/` `2` ` ` `# Driver Code ` `n ` `=` `3` `print` `(` `"3rd hexacontagon Number is = "` `, ` ` ` `hexacontagonNum(n)); ` ` ` `# This code is contributed by divyamohan123 ` |

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## C#

`// C# program for above approach ` `using` `System; ` ` ` `class` `GFG{ ` ` ` `// Finding the nth hexacontagon number ` `public` `static` `int` `hexacontagonNum(` `int` `n) ` `{ ` ` ` `return` `(58 * n * n - 56 * n) / 2; ` `} ` ` ` `// Driver code ` `public` `static` `void` `Main() ` `{ ` ` ` `int` `n = 3; ` ` ` `Console.Write(` `"3rd hexacontagon Number is = "` `+ ` ` ` `hexacontagonNum(n)); ` `} ` `} ` ` ` `// This code is contributed by Code_Mech ` |

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**Output:**

3rd hexacontagon Number is = 177

**Reference:** https://en.wikipedia.org/wiki/Hexacontagon

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