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Hectagon Number

Last Updated : 23 Jun, 2021
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Given a number N, the task is to find Nth hectagon number.
 

A hectagon number is class of figurate number. It has 100 – sided polygon called hectagon. The N-th hectagon number count’s the 100 number of dots and all others dots are surrounding with a common sharing corner and make a pattern. The first few hectagonol numbers are 1, 100, 297, 592 … 
 


Examples: 
 

Input: N = 2 
Output: 100 
Explanation: 
The second hectagonol number is 100. 
Input: N = 3 
Output: 297 
 


 


Approach: The N-th hectagon number is given by the formula:
 

  • Nth term of s sided polygon = \frac{((s-2)n^2 - (s-4)n)}{2}
     
  • Therefore Nth term of 100 sided polygon is
     

Tn =\frac{((100-2)n^2 - (100-4)n)}{2} =\frac{(98n^2 - 96)}{2}


  •  


Below is the implementation of the above approach:
 

C++

// C++ program for above approach
#include <bits/stdc++.h>
using namespace std;
 
// Finding the nth hectagon Number
int hectagonNum(int n)
{
    return (98 * n * n - 96 * n) / 2;
}
 
// Driver Code
int main()
{
    int n = 3;
    cout << "3rd hectagon Number is = "
         << hectagonNum(n);
 
    return 0;
}
 
// This code is contributed by shivanisinghss2110

                    

C

// C program for above approach
#include <stdio.h>
#include <stdlib.h>
 
// Finding the nth hectagon Number
int hectagonNum(int n)
{
    return (98 * n * n - 96 * n) / 2;
}
 
// Driver program to test above function
int main()
{
    int n = 3;
    printf("3rd hectagon Number is = %d",
           hectagonNum(n));
 
    return 0;
}

                    

Java

// Java program for above approach
import java.util.*;
class GFG{
 
// Finding the nth hectagon Number
static int hectagonNum(int n)
{
    return (98 * n * n - 96 * n) / 2;
}
 
// Driver Code
public static void main(String args[])
{
    int n = 3;
    System.out.print("3rd hectagon Number is = " +
                                  hectagonNum(n));
}
}
 
// This code is contributed by Akanksha_Rai

                    

Python3

# Python3 program for above approach
 
# Finding the nth hectagon number
def hectagonNum(n):
 
    return (98 * n * n - 96 * n) // 2
 
# Driver code
n = 3
print("3rd hectagon Number is = ",
                   hectagonNum(n))
 
# This code is contributed by divyamohan123

                    

C#

// C# program for above approach
using System;
class GFG{
 
// Finding the nth hectagon Number
static int hectagonNum(int n)
{
    return (98 * n * n - 96 * n) / 2;
}
 
// Driver Code
public static void Main()
{
    int n = 3;
    Console.Write("3rd hectagon Number is = " +
                               hectagonNum(n));
}
}
 
// This code is contributed by Akanksha_Rai

                    

Javascript

<script>
 
 
// JavaScript program for above approach
 
// Finding the nth hectagon Number
function hectagonNum(n)
{
    return (98 * n * n - 96 * n) / 2;
}
 
// Driver Code
var n = 3;
document.write("3rd hectagon Number is = "  + hectagonNum(n));
 
 
</script>

                    

Output: 
3rd hectagon Number is = 297

 

Time Complexity: O(1)

Auxiliary Space: O(1)

Reference: https://en.wiktionary.org/wiki/hectagon


 



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