GRE Quiz | GRE Quantitative 2 | Question 16

How many three digit number which are divisible by 6 and 3 both?

**(A)** 300**(B)** 299**(C)** 150**(D)** 149**(E)** 124**Answer:** **(C)****Explanation:** Divisibility rule by 6: the number must be an even number and sum of digit must be divisible by 3.

The first number which is divisible by 6 is 102 and the last number is 996. Applying arithmetic formula for finding number of terms with common difference (d) 6, first term(A_{1}) 102 and last term(A_{n}) 996:

A_{n}= A_{1}+ (n - 1)*d 996 = 102 + (n - 1)*6 n-1 = 894 / 6 = 149 n = 150

So, option (C) is correct.

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