Golang | Creating a string that contains regexp metacharacters
A regular expression is a sequence of characters which define a search pattern. Go language support regular expressions. A regular expression is used for parsing, filtering, validating, and extracting meaningful information from large text, like logs, the output generated from other programs, etc.
In Go regexp, you are allowed to create a string that escapes all regular expression metacharacters in the specified text with the help of QuoteMeta() function. The returned string of this function is a regular expression matching the literal text. This function is defined under the regexp package, so for accessing this method you need to import the regexp package in your program.
Syntax:
func QuoteMeta(str string) string
Example 1:
// Go program to illustrate how to create // a string that escapes all regular // expression metacharacters package main import ( "fmt" "regexp") // Main function func main() { // Escaping all regular // expression metacharacters // Using QuoteMeta () function res1 := regexp.QuoteMeta(`String 1: .+*()|[]{}^$`) fmt.Println(res1) res2 := regexp.QuoteMeta(`String 2: +()*`) fmt.Println(res2) res3 := regexp.QuoteMeta(`String 3: []|{}$`) fmt.Println(res3) res4 := regexp.QuoteMeta(`String 4: ^$*-,`) fmt.Println(res4) } |
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Output:
String 1: \.\+\*\(\)\|\[\]\{\}\^\$
String 2: \+\(\)\*
String 3: \[\]\|\{\}\$
String 4: \^\$\*-,
Example 2:
// Go program to illustrate how to create // a string that escapes all regular // expression metacharacters package main import ( "fmt" "regexp") // Main function func main() { // Creating and initializing string // Using shorthand declaration s1 := `+*?()|[]^$` s2 := `+*?()|[]^$ ` if s1 == s2 { // Escaping all regular // expression metacharacters // Using QuoteMeta () function res := regexp.QuoteMeta(s1) fmt.Println("String:", res) } else { fmt.Println("Not Equal") } } |
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Output:
Not Equal
