# Given 1’s, 2’s, 3’s ……k’s print them in zig zag way.

• Difficulty Level : Basic
• Last Updated : 25 May, 2021

Given number of rows and columns. And given number of 1’s, 2’s, 3’s ……k’s which needs to be printed. Print them in a zig-zag way.
It is guaranteed that n*m = number of 1’s + 2’s + 3’s + …… + k’s
Examples:

```Input :  2 3
2 1 2 1
Output : 1 1 2
4 3 3
Explanation :
Here number of rows are 2 and number of columns are 3
and number of 1's are 2
number of 2's are 1
number of 3's are 2
number of 4's are 1
-----------
| 1 | 1 | 2 |
| 3 | 3 | 4 |
-----------

Input :  4 3
2 4 3 1 2
Output : 1 1 2
2 2 2
3 3 3
5 5 4
Explanation :
Here number of rows are 4 and number of columns are 3
and number of 1's are 2
number of 2's are 4 [Note that 2s are printed in]
number of 3's are 3 [zig zag manner]
number of 4's are 1
number of 5's are 2```

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Approach: We make a two-dimensional array to store all the elements in zig-zag way. we will traverse through all the elements of an array of numbers and insert all the numbers of an array of i-th index into a two-dimensional array until it becomes zero.

## C++

 `// CPP program to print  given number of 1's,``// 2's, 3's ....k's in  zig-zag way.``#include ``using` `namespace` `std;` `// function that prints  given number of 1's,``// 2's, 3's ....k's in zig-zag way.``void` `ZigZag(``int` `rows, ``int` `columns, ``int` `numbers[])``{``    ``int` `k = 0;``    ` `    ``// two-dimensional array to store numbers.``    ``int` `arr[rows][columns];``    ` `    ``for` `(``int` `i=0; i0; j++)``            ``{``                ``// storing element.``                ``arr[i][j] = k+1;` `                ``// decrement element at``                ``// kth index.``                ``numbers[k]--;``                ` `                ``// if array contains zero``                ``// then increment index to``                ``// make this next index``                ``if` `(numbers[k] == 0)``                    ``k++;``            ``}``        ``}``        ` `        ``// for odd row.``        ``else``        ``{``            ``// for each column.``            ``for` `(``int` `j=columns-1; j>=0 and``                ``numbers[k]>0; j--)``            ``{``                ``// storing element.``                ``arr[i][j] = k+1;``                ` `                ``// decrement element``                ``// at kth index.``                ``numbers[k]--;``                ` `                ``// if array contains zero then``                ``// increment index to make this``                ``// next index.``                ``if` `(numbers[k]==0)``                    ``k++;``            ``}``        ``}``    ``}``    ` `    ``// printing the stored elements.``    ``for` `(``int` `i=0;i

## Java

 `// Java program to print given``// number of 1's, 2's, 3's ....k's``// in zig-zag way.``import` `java.util.*;``import` `java.lang.*;` `public` `class` `GfG{``    ` `    ``// function that prints given number of 1's,``    ``// 2's, 3's ....k's in zig-zag way.``    ``public` `static` `void` `ZigZag(``int` `rows,``                              ``int` `columns,``                              ``int` `numbers[])``    ``{``        ``int` `k = ``0``;``    ` `        ``// two-dimensional array to store numbers.``        ``int``[][] arr = ``new` `int``[rows][columns];``    ` `        ``for` `(``int` `i=``0``; i``0``; j++)``                ``{``                    ``// storing element.``                    ``arr[i][j] = k+``1``;` `                    ``// decrement element at``                    ``// kth index.``                    ``numbers[k]--;``                ` `                    ``// if array contains zero``                    ``// then increment index to``                    ``// make this next index``                    ``if` `(numbers[k] == ``0``)``                        ``k++;``                ``}``            ``}``        ` `            ``// for odd row.``            ``else``            ``{``                ``// for each column.``                ``for` `(``int` `j=columns-``1``; j>=``0` `&&``                    ``numbers[k]>``0``; j--)``                ``{``                    ``// storing element.``                    ``arr[i][j] = k+``1``;``                ` `                    ``// decrement element``                    ``// at kth index.``                    ``numbers[k]--;``                ` `                    ``// if array contains zero then``                    ``// increment index to make this``                    ``// next index.``                    ``if` `(numbers[k]==``0``)``                        ``k++;``                ``}``            ``}``        ``}``    ` `        ``// printing the stored elements.``        ``for` `(``int` `i=``0``;i

## Python 3

 `# Python3 program to print given number of 1's,``# 2's, 3's ....k's in zig-zag way.` `# function that prints given number of 1's,``# 2's, 3's ....k's in zig-zag way.``def` `ZigZag(rows, columns, numbers):``    ``k ``=` `0``    ` `    ``# two-dimensional array to store numbers.``    ``arr ``=` `[[``0` `for` `i ``in` `range``(columns)] ``for` `j ``in` `range``(rows)]``    ``for` `i ``in` `range``(rows):``        ` `        ``# for even row.``        ``if` `(i ``%` `2` `=``=` `0``):``            ` `            ``# for each column.``            ``j ``=` `0``            ``while` `j < columns ``and` `numbers[k] > ``0``:``                ` `                ``# storing element.``                ``arr[i][j] ``=` `k ``+` `1``                ` `                ``# decrement element at``                ``# kth index.``                ``numbers[k] ``-``=` `1`   `                ` `                ``# if array contains zero``                ``# then increment index to``                ``# make this next index``                ``if` `numbers[k] ``=``=` `0``:``                    ``k ``+``=` `1``                ``j ``+``=` `1``        ``# for odd row.``        ``else``:``            ` `            ``# for each column.``            ``j ``=` `columns``-``1``            ``while` `j>``=``0` `and` `numbers[k]>``0``:``                ` `                ``# storing element.``                ``arr[i][j] ``=` `k``+``1``                ` `                ``# decrement element``                ``# at kth index.``                ``numbers[k] ``-``=` `1``                ` `                ``# if array contains zero then``                ``# increment index to make this``                ``# next index.``                ``if` `numbers[k] ``=``=` `0``:``                    ``k ``+``=` `1``                ``j ``-``=` `1``    ` `    ``# printing the stored elements.``    ``for` `i ``in` `arr:``        ``for` `j ``in` `i:``            ``print``(j, end ``=``" "``)``        ``print``()` `# Driver code``rows ``=` `4``;``columns ``=` `5``;``Numbers ``=` `[``3``, ``4``, ``2``, ``2``, ``3``, ``1``, ``5``]``ZigZag(rows, columns, Numbers)` `# This code is contributed by``# Rajnis09`

## C#

 `// C# program to print given``// number of 1's, 2's, 3's ....k's``// in zig-zag way.``using` `System;` `public` `class` `GfG{``    ` `    ``// function that prints given number of 1's,``    ``// 2's, 3's ....k's in zig-zag way.``    ``public` `static` `void` `ZigZag(``int` `rows,``                            ``int` `columns,``                            ``int` `[]numbers)``    ``{``        ``int` `k = 0;``    ` `        ``// two-dimensional array to store numbers.``        ``int``[,] arr = ``new` `int``[rows,columns];``    ` `        ``for` `(``int` `i = 0; i < rows; i++)``        ``{``            ``// for even row.``            ``if` `(i % 2 == 0)``            ``{``                ``// for each column.``                ``for` `(``int` `j = 0; j < columns &&``                        ``numbers[k] > 0; j++)``                ``{``                    ``// storing element.``                    ``arr[i,j] = k + 1;` `                    ``// decrement element at``                ``// kth index.``                    ``numbers[k]--;``                ` `                    ``// if array contains zero``                    ``// then increment index to``                    ``// make this next index``                    ``if` `(numbers[k] == 0)``                        ``k++;``                ``}``            ``}``        ` `            ``// for odd row.``            ``else``            ``{``                ``// for each column.``                ``for` `(``int` `j = columns - 1; j >= 0 &&``                    ``numbers[k] > 0; j--)``                ``{``                    ``// storing element.``                    ``arr[i,j] = k + 1;``                ` `                    ``// decrement element``                    ``// at kth index.``                    ``numbers[k]--;``                ` `                    ``// if array contains zero then``                    ``// increment index to make this``                    ``// next index.``                    ``if` `(numbers[k] == 0)``                        ``k++;``                ``}``            ``}``        ``}``    ` `        ``// printing the stored elements.``        ``for` `(``int` `i = 0;i < rows; i++)``        ``{``            ``for` `(``int` `j = 0; j < columns; j++)``            ``Console.Write(arr[i, j] + ``" "``);``            ` `            ``Console.WriteLine();``        ``}``    ``}``    ` `    ``// Driver function``    ``public` `static` `void` `Main()``    ``{``        ``int` `rows = 4;``        ``int` `columns = 5;``        ``int` `[]Numbers = ``new` `int``[]{3, 4, 2,``                                ``2, 3, 1, 5};``        ``ZigZag(rows, columns, Numbers);``    ``}``}` `/* This code is contributed by vt_m*/`

## PHP

 ` 0; ``\$j``++)``            ``{``                ` `                ``// storing element.``                ``\$arr``[``\$i``][``\$j``] = ``\$k` `+ 1;` `                ``// decrement element at``                ``// kth index.``                ``\$numbers``[``\$k``]--;``                ` `                ``// if array contains zero``                ``// then increment index to``                ``// make this next index``                ``if` `(``\$numbers``[``\$k``] == 0)``                    ``\$k``++;``            ``}``        ``}``        ` `        ``// for odd row.``        ``else``        ``{``            ` `            ``// for each column.``            ``for``(``\$j` `= ``\$columns` `- 1; ``\$j` `>= 0 ``and``                       ``\$numbers``[``\$k``] > 0; ``\$j``--)``            ``{``                ` `                ``// storing element.``                ``\$arr``[``\$i``][``\$j``] = ``\$k` `+ 1;``                ` `                ``// decrement element``                ``// at kth index.``                ``\$numbers``[``\$k``]--;``                ` `                ``// if array contains zero then``                ``// increment index to make this``                ``// next index.``                ``if` `(``\$numbers``[``\$k``]==0)``                    ``\$k``++;``            ``}``        ``}``    ``}``    ` `    ``// printing the stored elements.``    ``for``(``\$i` `= 0; ``\$i` `< ``\$rows``;``\$i``++)``    ``{``        ``for``(``\$j` `= 0; ``\$j` `< ``\$columns``; ``\$j``++)``            ``echo` `\$arr``[``\$i``][``\$j``] , ``" "``;``            ` `        ``echo` `"\n"``;``    ``}``}` `    ``// Driver Code``    ``\$rows` `= 4;``    ``\$columns` `= 5;``    ``\$Numbers` `= ``array``(3, 4, 2, 2, 3, 1, 5);``    ``ZigZag(``\$rows``, ``\$columns``,``\$Numbers``);``    ` `// This code is contributed by anuj_67.``?>`

## Javascript

 ``

Output:

```1 1 1 2 2
4 3 3 2 2
4 5 5 5 6
7 7 7 7 7```

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