Given 1’s, 2’s, 3’s ……k’s print them in zig zag way.

Given number of rows and columns. And given number of 1’s, 2’s, 3’s ……k’s which needs to be printed. Print them in a zig-zag way. 
It is guaranteed that n*m = number of 1’s + 2’s + 3’s + …… + k’s 

Examples: 

Input :  2 3
         2 1 2 1
Output : 1 1 2
         4 3 3
Explanation :
Here number of rows are 2 and number of columns are 3
and number of 1's are 2
    number of 2's are 1
    number of 3's are 2
    number of 4's are 1
    -----------
   | 1 | 1 | 2 |
   | 3 | 3 | 4 |
    -----------

Input :  4 3
         2 4 3 1 2
Output : 1 1 2
         2 2 2
         3 3 3
         5 5 4
Explanation :
Here number of rows are 4 and number of columns are 3
and number of 1's are 2
    number of 2's are 4 [Note that 2s are printed in]
    number of 3's are 3 [zig zag manner]
    number of 4's are 1
    number of 5's are 2

Approach: We make a two-dimensional array to store all the elements in zig-zag way. we will traverse through all the elements of an array of numbers and insert all the numbers of an array of i-th index into a two-dimensional array until it becomes zero. 

Implementation:

C++

// CPP program to print  given number of 1's,
// 2's, 3's ....k's in  zig-zag way.
#include <bits/stdc++.h>
using namespace std;

// function that prints  given number of 1's,
// 2's, 3's ....k's in zig-zag way.
void ZigZag(int rows, int columns, int numbers[])
{
    int k = 0;

    // two-dimensional array to store numbers.
    int arr[rows][columns];

    for (int i=0; i<rows; i++)
    {
        // for even row.
        if (i%2==0)
        {
            // for each column.
            for (int j=0; j<columns and
                    numbers[k]>0; j++)
            {
                // storing element.
                arr[i][j] = k+1;

                // decrement element at
                // kth index.
                numbers[k]--;

                // if array contains zero
                // then increment index to
                // make this next index
                if (numbers[k] == 0)
                    k++;
            }
        }

        // for odd row.
        else
        {
            // for each column.
            for (int j=columns-1; j>=0 and
                numbers[k]>0; j--)
            {
                // storing element.
                arr[i][j] = k+1;

                // decrement element
                // at kth index.
                numbers[k]--;

                // if array contains zero then
                // increment index to make this
                // next index.
                if (numbers[k]==0)
                    k++;
            }
        }
    }

    // printing the stored elements.
    for (int i=0;i<rows;i++)
    {
        for (int j=0;j<columns;j++)
            cout << arr[i][j] << " ";

        cout << endl;
    }
}

// Driver code for above function.
int main()
{
    int rows = 4;
    int columns = 5;
    int Numbers[] = {3, 4, 2, 2, 3, 1, 5};
    ZigZag(rows, columns, Numbers);
    return 0;
}

C

// C program to print  given number of 1's,
// 2's, 3's ....k's in  zig-zag way.
#include <stdio.h>

// function that prints  given number of 1's,
// 2's, 3's ....k's in zig-zag way.
void ZigZag(int rows, int columns, int numbers[])
{
    int k = 0;

    // two-dimensional array to store numbers.
    int arr[rows][columns];

    for (int i=0; i<rows; i++)
    {
        // for even row.
        if (i%2==0)
        {
            // for each column.
            for (int j=0; j<columns && numbers[k]>0; j++)
            {
                // storing element.
                arr[i][j] = k+1;

                // decrement element at
                // kth index.
                numbers[k]--;

                // if array contains zero
                // then increment index to
                // make this next index
                if (numbers[k] == 0)
                    k++;
            }
        }

        // for odd row.
        else
        {
            // for each column.
            for (int j=columns-1; j>=0 && numbers[k]>0; j--)
            {
                // storing element.
                arr[i][j] = k+1;

                // decrement element
                // at kth index.
                numbers[k]--;

                // if array contains zero then
                // increment index to make this
                // next index.
                if (numbers[k]==0)
                    k++;
            }
        }
    }

    // printing the stored elements.
    for (int i=0;i<rows;i++)
    {
        for (int j=0;j<columns;j++)
            printf("%d ",arr[i][j]);

        printf("\n");
    }
}

// Driver code for above function.
int main()
{
    int rows = 4;
    int columns = 5;
    int Numbers[] = {3, 4, 2, 2, 3, 1, 5};
    ZigZag(rows, columns, Numbers);
    return 0;
}

// This code is contributed by kothavvsaakash.

Java

// Java program to print given
// number of 1's, 2's, 3's ....k's
// in zig-zag way.
import java.util.*;
import java.lang.*;

public class GfG{

    // function that prints given number of 1's,
    // 2's, 3's ....k's in zig-zag way.
    public static void ZigZag(int rows,
                              int columns,
                              int numbers[])
    {
        int k = 0;

        // two-dimensional array to store numbers.
        int[][] arr = new int[rows][columns];

        for (int i=0; i<rows; i++)
        {
            // for even row.
            if (i%2==0)
            {
                // for each column.
                for (int j=0; j<columns &&
                        numbers[k]>0; j++)
                {
                    // storing element.
                    arr[i][j] = k+1;

                    // decrement element at
                    // kth index.
                    numbers[k]--;

                    // if array contains zero
                    // then increment index to
                    // make this next index
                    if (numbers[k] == 0)
                        k++;
                }
            }

            // for odd row.
            else
            {
                // for each column.
                for (int j=columns-1; j>=0 &&
                    numbers[k]>0; j--)
                {
                    // storing element.
                    arr[i][j] = k+1;

                    // decrement element
                    // at kth index.
                    numbers[k]--;

                    // if array contains zero then
                    // increment index to make this
                    // next index.
                    if (numbers[k]==0)
                        k++;
                }
            }
        }

        // printing the stored elements.
        for (int i=0;i<rows;i++)
        {
            for (int j=0;j<columns;j++)
                System.out.print(arr[i][j] + " ");

            System.out.println();
        }
    }

    // Driver function
    public static void main(String argc[])
    {
        int rows = 4;
        int columns = 5;
        int[] Numbers = new int[]{3, 4, 2,
                                  2, 3, 1, 5};
        ZigZag(rows, columns, Numbers);
    }
}

/* This code is contributed by Sagar Shukla */

Python 3

# Python3 program to print given number of 1's,
# 2's, 3's ....k's in zig-zag way.

# function that prints given number of 1's,
# 2's, 3's ....k's in zig-zag way.
def ZigZag(rows, columns, numbers):
    k = 0

    # two-dimensional array to store numbers.
    arr = [[0 for i in range(columns)] for j in range(rows)]
    for i in range(rows):

        # for even row.
        if (i % 2 == 0):

            # for each column.
            j = 0
            while j < columns and numbers[k] > 0:

                # storing element.
                arr[i][j] = k + 1

                # decrement element at
                # kth index.
                numbers[k] -= 1

                # if array contains zero
                # then increment index to
                # make this next index
                if numbers[k] == 0:
                    k += 1
                j += 1
        # for odd row.
        else:

            # for each column.
            j = columns-1
            while j>=0 and numbers[k]>0:

                # storing element.
                arr[i][j] = k+1

                # decrement element
                # at kth index.
                numbers[k] -= 1

                # if array contains zero then
                # increment index to make this
                # next index.
                if numbers[k] == 0:
                    k += 1
                j -= 1

    # printing the stored elements.
    for i in arr:
        for j in i:
            print(j, end =" ")
        print()

# Driver code
rows = 4;
columns = 5;
Numbers = [3, 4, 2, 2, 3, 1, 5]
ZigZag(rows, columns, Numbers)

# This code is contributed by
# Rajnis09

C#

// C# program to print given
// number of 1's, 2's, 3's ....k's
// in zig-zag way.
using System;

public class GfG{

    // function that prints given number of 1's,
    // 2's, 3's ....k's in zig-zag way.
    public static void ZigZag(int rows,
                            int columns,
                            int []numbers)
    {
        int k = 0;

        // two-dimensional array to store numbers.
        int[,] arr = new int[rows,columns];

        for (int i = 0; i < rows; i++)
        {
            // for even row.
            if (i % 2 == 0)
            {
                // for each column.
                for (int j = 0; j < columns &&
                        numbers[k] > 0; j++)
                {
                    // storing element.
                    arr[i,j] = k + 1;

                    // decrement element at
                // kth index.
                    numbers[k]--;

                    // if array contains zero
                    // then increment index to
                    // make this next index
                    if (numbers[k] == 0)
                        k++;
                }
            }

            // for odd row.
            else
            {
                // for each column.
                for (int j = columns - 1; j >= 0 &&
                    numbers[k] > 0; j--)
                {
                    // storing element.
                    arr[i,j] = k + 1;

                    // decrement element
                    // at kth index.
                    numbers[k]--;

                    // if array contains zero then
                    // increment index to make this
                    // next index.
                    if (numbers[k] == 0)
                        k++;
                }
            }
        }

        // printing the stored elements.
        for (int i = 0;i < rows; i++)
        {
            for (int j = 0; j < columns; j++)
            Console.Write(arr[i, j] + " ");

            Console.WriteLine();
        }
    }

    // Driver function
    public static void Main()
    {
        int rows = 4;
        int columns = 5;
        int []Numbers = new int[]{3, 4, 2,
                                2, 3, 1, 5};
        ZigZag(rows, columns, Numbers);
    }
}

/* This code is contributed by vt_m*/

PHP

<?php
// PHP program to print given number of 1's,
// 2's, 3's ....k's in zig-zag way.

// function that prints given number of 1's,
// 2's, 3's ....k's in zig-zag way.
function ZigZag($rows, $columns, $numbers)
{
    $k = 0;

    // two-dimensional array
    // to store numbers.
    $arr = array(array());

    for($i = 0; $i < $rows; $i++)
    {

        // for even row.
        if ($i % 2==0)
        {

            // for each column.
            for($j = 0; $j < $columns and
                  $numbers[$k] > 0; $j++)
            {

                // storing element.
                $arr[$i][$j] = $k + 1;

                // decrement element at
                // kth index.
                $numbers[$k]--;

                // if array contains zero
                // then increment index to
                // make this next index
                if ($numbers[$k] == 0)
                    $k++;
            }
        }

        // for odd row.
        else
        {

            // for each column.
            for($j = $columns - 1; $j >= 0 and
                       $numbers[$k] > 0; $j--)
            {

                // storing element.
                $arr[$i][$j] = $k + 1;

                // decrement element
                // at kth index.
                $numbers[$k]--;

                // if array contains zero then
                // increment index to make this
                // next index.
                if ($numbers[$k]==0)
                    $k++;
            }
        }
    }

    // printing the stored elements.
    for($i = 0; $i < $rows;$i++)
    {
        for($j = 0; $j < $columns; $j++)
            echo $arr[$i][$j] , " ";

        echo "\n";
    }
}

    // Driver Code
    $rows = 4;
    $columns = 5;
    $Numbers = array(3, 4, 2, 2, 3, 1, 5);
    ZigZag($rows, $columns,$Numbers);

// This code is contributed by anuj_67.
?>

Javascript

<script>

    // JavaScript program to print given
    // number of 1's, 2's, 3's ....k's
    // in zig-zag way.

    // function that prints given number of 1's,
    // 2's, 3's ....k's in zig-zag way.
    function ZigZag(rows, columns, numbers)
    {
        let k = 0;

        // two-dimensional array to store numbers.
        let arr = new Array(rows);
          for (let i=0; i<rows; i++)
        {
            arr[i] = new Array(rows);
            for (let j=0; j < columns; j++)
            {
                arr[i][j] = 0;
            }
        }

        for (let i=0; i<rows; i++)
        {
            // for even row.
            if (i%2==0)
            {
                // for each column.
                for (let j=0; j<columns &&
                        numbers[k]>0; j++)
                {
                    // storing element.
                    arr[i][j] = k+1;

                    // decrement element at
                    // kth index.
                    numbers[k]--;

                    // if array contains zero
                    // then increment index to
                    // make this next index
                    if (numbers[k] == 0)
                        k++;
                }
            }

            // for odd row.
            else
            {
                // for each column.
                for (let j=columns-1; j>=0 &&
                    numbers[k]>0; j--)
                {
                    // storing element.
                    arr[i][j] = k+1;

                    // decrement element
                    // at kth index.
                    numbers[k]--;

                    // if array contains zero then
                    // increment index to make this
                    // next index.
                    if (numbers[k]==0)
                        k++;
                }
            }
        }

        // printing the stored elements.
        for (let i=0;i<rows;i++)
        {
            for (let j=0;j<columns;j++)
                document.write(arr[i][j] + " ");

            document.write("</br>");
        }
    }

    let rows = 4;
    let columns = 5;
    let Numbers = [3, 4, 2, 2, 3, 1, 5];
    ZigZag(rows, columns, Numbers);

</script>

Output

1 1 1 2 2 
4 3 3 2 2 
4 5 5 5 6 
7 7 7 7 7 

Time Complexity: O(N*M), as we are using nested loops for traversing the matrix.
Auxiliary Space: O(N*M), as we are using extra space.