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# Get Level of a node in a Binary Tree

• Difficulty Level : Easy
• Last Updated : 05 Jul, 2021

Given a Binary Tree and a key, write a function that returns level of the key.
For example, consider the following tree. If the input key is 3, then your function should return 1. If the input key is 4, then your function should return 3. And for key which is not present in key, then your function should return 0. The idea is to start from the root and level as 1. If the key matches with root’s data, return level. Else recursively call for left and right subtrees with level as level + 1.

## C++

 `// C++ program to Get Level of a``// node in a Binary Tree``#include``using` `namespace` `std;` `/* A tree node structure */``struct` `node``{``    ``int` `data;``    ``struct` `node *left;``    ``struct` `node *right;``};` `/* Helper function for getLevel().``It returns level of the data if data is``present in tree, otherwise returns 0.*/``int` `getLevelUtil(``struct` `node *node,``                 ``int` `data, ``int` `level)``{``    ``if` `(node == NULL)``        ``return` `0;` `    ``if` `(node -> data == data)``        ``return` `level;` `    ``int` `downlevel = getLevelUtil(node -> left,``                                 ``data, level + 1);``    ``if` `(downlevel != 0)``        ``return` `downlevel;` `    ``downlevel = getLevelUtil(node->right,``                             ``data, level + 1);``    ``return` `downlevel;``}` `/* Returns level of given data value */``int` `getLevel(``struct` `node *node, ``int` `data)``{``    ``return` `getLevelUtil(node, data, 1);``}` `/* Utility function to create a``new Binary Tree node */``struct` `node* newNode(``int` `data)``{``    ``struct` `node *temp = ``new` `struct` `node;``    ``temp -> data = data;``    ``temp -> left = NULL;``    ``temp -> right = NULL;` `    ``return` `temp;``}` `// Driver Code``int` `main()``{``    ``struct` `node *root = ``new` `struct` `node;``    ``int` `x;` `    ``/* Constructing tree given in``    ``the above figure */``    ``root = newNode(3);``    ``root->left = newNode(2);``    ``root->right = newNode(5);``    ``root->left->left = newNode(1);``    ``root->left->right = newNode(4);` `    ``for` `(x = 1; x <= 5; x++)``    ``{``        ``int` `level = getLevel(root, x);``        ``if` `(level)``            ``cout << ``"Level of "``<< x << ``" is "``                 ``<< getLevel(root, x) << endl;``        ``else``            ``cout << x << ``"is not present in tree"``                      ``<< endl;``    ``}` `    ``getchar``();``    ``return` `0;``}` `// This code is contributed``// by Akanksha Rai`

## C

 `// C program to Get Level of a node in a Binary Tree``#include``#include` `/* A tree node structure */``struct` `node``{``    ``int` `data;``    ``struct` `node *left;``    ``struct` `node *right;``};` `/* Helper function for getLevel(). ``    ``It returns level of the data if data is``   ``present in tree, otherwise returns 0.*/``int` `getLevelUtil(``struct` `node *node,``                 ``int` `data, ``int` `level)``{``    ``if` `(node == NULL)``        ``return` `0;` `    ``if` `(node->data == data)``        ``return` `level;` `    ``int` `downlevel = getLevelUtil(node->left,``                                 ``data, level+1);``    ``if` `(downlevel != 0)``        ``return` `downlevel;` `    ``downlevel = getLevelUtil(node->right,``                             ``data, level+1);``    ``return` `downlevel;``}` `/* Returns level of given data value */``int` `getLevel(``struct` `node *node, ``int` `data)``{``    ``return` `getLevelUtil(node,data,1);``}` `/* Utility function to create``   ``a new Binary Tree node */``struct` `node* newNode(``int` `data)``{``    ``struct` `node *temp = (``struct` `node*)``malloc``(``sizeof``(``struct` `node));``    ``temp->data = data;``    ``temp->left = NULL;``    ``temp->right = NULL;` `    ``return` `temp;``}` `/* Driver code */``int` `main()``{``    ``struct` `node *root;``    ``int` `x;` `    ``/* Constructing tree given``       ``in the above figure */``    ``root = newNode(3);``    ``root->left = newNode(2);``    ``root->right = newNode(5);``    ``root->left->left = newNode(1);``    ``root->left->right = newNode(4);` `    ``for` `(x = 1; x <=5; x++)``    ``{``      ``int` `level = getLevel(root, x);``      ``if` `(level)``        ``printf``(``" Level of %d is %d\n"``, x, getLevel(root, x));``      ``else``        ``printf``(``" %d is not present in tree \n"``, x);` `    ``}` `    ``getchar``();``    ``return` `0;``}`

## Java

 `// Java program to Get Level of a node in a Binary Tree``/* A tree node structure */``class` `Node {``    ``int` `data;``    ``Node left, right;` `    ``public` `Node(``int` `d)``    ``{``        ``data = d;``        ``left = right = ``null``;``    ``}``}` `class` `BinaryTree {` `    ``Node root;` `    ``/* Helper function for getLevel().``       ``It returns level of``       ``the data if data is present in tree,``       ``otherwise returns``       ``0.*/``    ``int` `getLevelUtil(Node node, ``int` `data, ``int` `level)``    ``{``        ``if` `(node == ``null``)``            ``return` `0``;` `        ``if` `(node.data == data)``            ``return` `level;` `        ``int` `downlevel``            ``= getLevelUtil(node.left, data, level + ``1``);``        ``if` `(downlevel != ``0``)``            ``return` `downlevel;` `        ``downlevel``            ``= getLevelUtil(node.right, data, level + ``1``);``        ``return` `downlevel;``    ``}` `    ``/* Returns level of given data value */``    ``int` `getLevel(Node node, ``int` `data)``    ``{``        ``return` `getLevelUtil(node, data, ``1``);``    ``}` `    ``/* Driver code */``    ``public` `static` `void` `main(String[] args)``    ``{``        ``BinaryTree tree = ``new` `BinaryTree();` `        ``/* Constructing tree given in the above figure */``        ``tree.root = ``new` `Node(``3``);``        ``tree.root.left = ``new` `Node(``2``);``        ``tree.root.right = ``new` `Node(``5``);``        ``tree.root.left.left = ``new` `Node(``1``);``        ``tree.root.left.right = ``new` `Node(``4``);``        ``for` `(``int` `x = ``1``; x <= ``5``; x++)``        ``{``            ``int` `level = tree.getLevel(tree.root, x);``            ``if` `(level != ``0``)``                ``System.out.println(``                    ``"Level of "` `+ x + ``" is "``                    ``+ tree.getLevel(tree.root, x));``            ``else``                ``System.out.println(``                    ``x + ``" is not present in tree"``);``        ``}``    ``}``}` `// This code has been contributed by Mayank``// Jaiswal(mayank_24)`

## Python3

 `# Python3 program to Get Level of a``# node in a Binary Tree` `# Helper function that allocates a``# new node with the given data and``# None left and right pairs.`  `class` `newNode:` `    ``# Constructor to create a new node``    ``def` `__init__(``self``, data):``        ``self``.data ``=` `data``        ``self``.left ``=` `None``        ``self``.right ``=` `None` `# Helper function for getLevel(). It``# returns level of the data if data is``# present in tree, otherwise returns 0`  `def` `getLevelUtil(node, data, level):``    ``if` `(node ``=``=` `None``):``        ``return` `0` `    ``if` `(node.data ``=``=` `data):``        ``return` `level` `    ``downlevel ``=` `getLevelUtil(node.left,``                             ``data, level ``+` `1``)``    ``if` `(downlevel !``=` `0``):``        ``return` `downlevel` `    ``downlevel ``=` `getLevelUtil(node.right,``                             ``data, level ``+` `1``)``    ``return` `downlevel` `# Returns level of given data value`  `def` `getLevel(node, data):` `    ``return` `getLevelUtil(node, data, ``1``)`  `# Driver Code``if` `__name__ ``=``=` `'__main__'``:` `    ``# Let us construct the Tree shown``    ``# in the above figure``    ``root ``=` `newNode(``3``)``    ``root.left ``=` `newNode(``2``)``    ``root.right ``=` `newNode(``5``)``    ``root.left.left ``=` `newNode(``1``)``    ``root.left.right ``=` `newNode(``4``)``    ``for` `x ``in` `range``(``1``, ``6``):``        ``level ``=` `getLevel(root, x)``        ``if` `(level):``            ``print``(``"Level of"``, x,``                  ``"is"``, getLevel(root, x))``        ``else``:``            ``print``(x, ``"is not present in tree"``)` `# This code is contributed by``# Shubham Singh(SHUBHAMSINGH10)`

## C#

 `// C# program to Get Level of a node in a Binary Tree``using` `System;` `/* A tree node structure */``public` `class` `Node {``    ``public` `int` `data;``    ``public` `Node left, right;` `    ``public` `Node(``int` `d)``    ``{``        ``data = d;``        ``left = right = ``null``;``    ``}``}` `public` `class` `BinaryTree {` `    ``public` `Node root;` `    ``/* Helper function for getLevel().``       ``It returns level of``       ``the data if data is present in tree,``      ``otherwise returns``    ``0.*/``    ``public` `virtual` `int` `getLevelUtil(Node node, ``int` `data,``                                    ``int` `level)``    ``{``        ``if` `(node == ``null``)``        ``{``            ``return` `0;``        ``}` `        ``if` `(node.data == data)``        ``{``            ``return` `level;``        ``}` `        ``int` `downlevel``            ``= getLevelUtil(node.left, data, level + 1);``        ``if` `(downlevel != 0)``        ``{``            ``return` `downlevel;``        ``}` `        ``downlevel``            ``= getLevelUtil(node.right, data, level + 1);``        ``return` `downlevel;``    ``}` `    ``/* Returns level of given data value */``    ``public` `virtual` `int` `getLevel(Node node, ``int` `data)``    ``{``        ``return` `getLevelUtil(node, data, 1);``    ``}` `    ``/* Driver code */``    ``public` `static` `void` `Main(``string``[] args)``    ``{``        ``BinaryTree tree = ``new` `BinaryTree();` `        ``/* Constructing tree given in the above figure */``        ``tree.root = ``new` `Node(3);``        ``tree.root.left = ``new` `Node(2);``        ``tree.root.right = ``new` `Node(5);``        ``tree.root.left.left = ``new` `Node(1);``        ``tree.root.left.right = ``new` `Node(4);``        ``for` `(``int` `x = 1; x <= 5; x++)``        ``{``            ``int` `level = tree.getLevel(tree.root, x);``            ``if` `(level != 0)``            ``{``                ``Console.WriteLine(``                    ``"Level of "` `+ x + ``" is "``                    ``+ tree.getLevel(tree.root, x));``            ``}``            ``else``            ``{``                ``Console.WriteLine(``                    ``x + ``" is not present in tree"``);``            ``}``        ``}``    ``}``}` `// This code is contributed by Shrikant13`

## Javascript

 ``
Output
```Level of 1 is 3
Level of 2 is 2
Level of 3 is 1
Level of 4 is 3
Level of 5 is 2```

Time Complexity of getLevel() is O(n) where n is the number of nodes in the given Binary Tree.