Generate Infinite Stream of Double in Java
Last Updated :
11 Dec, 2018
Given the task is to generate an infinite sequential unordered stream of double in Java.
This can be done in following ways:
- Using DoubleStream.iterate():
- Using the DoubleStream.iterate() method, iterate the DoubleStream with i by incrementing the value with 1.
- Print the DoubleStream with the help of forEach() method.
import java.util.stream.*;
public class GFG {
public static void main(String[] args)
{
DoubleStream
.iterate( 0 , i -> i + 1 )
.forEach(System.out::println);
}
}
|
Output:
0.0
1.0
2.0
3.0
4.0
5.0
6.0
.
.
.
- Using Random.doubles():
- Get the next double using doubles() method
- Print the DoubleStream with the help of forEach() method.
import java.util.stream.*;
import java.util.*;
public class GFG {
public static void main(String[] args)
{
Random random = new Random();
random
.doubles()
.forEach(System.out::println);
}
}
|
Output:
0.3668625445505631
0.4385898887922953
0.23333911864591927
0.7134958163360963
0.6945667694181287
0.6898427735417596
0.9243923588584183
.
.
.
- Using DoubleStream.generate() method:
- Generate the next double using DoubleStream.generate() and Random.nextDouble()
- Print the DoubleStream with the help of forEach() method.
import java.util.stream.*;
import java.util.*;
public class GFG {
public static void main(String[] args)
{
Random random = new Random();
DoubleStream
.generate(random::nextDouble)
.forEach(System.out::println);
}
}
|
Output:
0.025801080723973246
0.5115037630832635
0.030815898624858784
0.5441584143944648
0.6984267528746901
0.5821292304544626
.
.
.
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