# Generate all possible strings formed by replacing letters with given respective symbols

• Last Updated : 23 Jul, 2021

Given a string S consisting of N characters and an array M[] of pairs of characters such that any character M[i] can be replaced with the character M[i] in the string S, the task is to generate all the possible strings formed by replacing some characters of the string with their respective symbols in the array M[].

Examples:

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Input: S = “aBc”, M = {‘a’ : ‘\$’, ‘B’ : ‘#’, ‘c’ : ‘^’}
Output:
aBc
aB^
a#c
a#^
\$Bc
\$B^
\$#c
\$#^

Input: S = “a”, M={‘a’ : ‘\$’}
Output:
a
\$

Approach: The given problem can be solved by using Backtracking to generate all possible strings by replacing each character with the mapped character in the array M[]. Follow the steps below to solve the problem:

• Store all the pairs of the mapped characters in the array M[] in a map, say Map.
• Define a recursive function say generateLetters(S, P), where S is the modified string and P is the index of the current character:
• Check for the base case i.e., if index P equals to the N then print the string S and return.
• Do not change the current character and recursively call for the function, generateLetters(S, P + 1).
• Now, replace the character, S[P] with the respective symbol in the map M and call for the function, generateLetters(S, P+1).
• After completing the above steps, call for the function generateLetters(S, 0) to print all possible strings.

Below is the implementation of the above approach:

## C++

 `// C++ program for the above approach` `#include ``using` `namespace` `std;` `// Function to generate all possible``// string by replacing the characters``// with mapped symbols``void` `generateLetters(string S, ``int` `P,``                     ``unordered_map<``char``, ``char``> M)``{``    ``// Base Case``    ``if` `(P == S.size()) {``        ``cout << S << ``"\n"``;``        ``return``;``    ``}` `    ``// Function call with the P-th``    ``// character not replaced``    ``generateLetters(S, P + 1, M);` `    ``// Replace the P-th character``    ``S[P] = M[S[P]];` `    ``// Function call with the P-th``    ``// character replaced``    ``generateLetters(S, P + 1, M);` `    ``return``;``}` `// Driver Code``int` `main()``{``    ``string S = ``"aBc"``;``    ``unordered_map<``char``, ``char``> M;``    ``M[``'a'``] = ``'\$'``;``    ``M[``'B'``] = ``'#'``;``    ``M[``'c'``] = ``'^'``;``    ``M[``'d'``] = ``'&'``;``    ``M[``'1'``] = ``'*'``;``    ``M[``'2'``] = ``'!'``;``    ``M[``'E'``] = ``'@'``;` `    ``// Function Call``    ``generateLetters(S, 0, M);` `    ``return` `0;``}`

## Java

 `// Java program for the above approach``import` `java.util.HashMap;` `class` `GFG{` `// Function to generate all possible``// string by replacing the characters``// with mapped symbols``public` `static` `void` `generateLetters(String S, ``int` `P, HashMap M)``{``    ``// Base Case``    ``if` `(P == S.length()) {``        ``System.out.println(S);``        ``return``;``    ``}` `    ``// Function call with the P-th``    ``// character not replaced``    ``generateLetters(S, P + ``1``, M);` `    ``// Replace the P-th character``    ``S = S.substring(``0``, P) + M.get(S.charAt(P)) + S.substring(P + ``1``);` `    ``// Function call with the P-th``    ``// character replaced``    ``generateLetters(S, P + ``1``, M);` `    ``return``;``}` `// Driver Code``public` `static` `void` `main(String args[])``{``    ``String S = ``"aBc"``;``    ``HashMap M = ``new` `HashMap();``    ``M.put(``'a'``, ``'\$'``);``    ``M.put(``'B'``, ``'#'``);``    ``M.put(``'c'``, ``'^'``);``    ``M.put(``'d'``, ``'&'``);``    ``M.put(``'1'``, ``'*'``);``    ``M.put(``'2'``, ``'!'``);``    ``M.put(``'E'``, ``'@'``);` `    ``// Function Call``    ``generateLetters(S, ``0``, M);` `}` `}` `// This code is contributed by _saurabh_jaiswal.`

## Python3

 `# Python program for the above approach` `# Function to generate all possible``# string by replacing the characters``# with mapped symbols``def` `generateLetters(S, P, M):` `    ``# Base Case``    ``if` `(P ``=``=` `len``(S)):``        ``print``(S);``        ``return` `    ``# Function call with the P-th``    ``# character not replaced``    ``generateLetters(S, P ``+` `1``, M);` `    ``# Replace the P-th character``    ``S ``=` `S.replace(S[P], M[S[P]])` `    ``# Function call with the P-th``    ``# character replaced``    ``generateLetters(S, P ``+` `1``, M);` `# Driver Code``S ``=` `"aBc"``;``M ``=` `{};``M[``'a'``] ``=` `'\$'``M[``'B'``] ``=` `'#'``M[``'c'``] ``=` `'^'``M[``'d'``] ``=` `'&'``M[``'1'``] ``=` `'*'``M[``'2'``] ``=` `'!'``M[``'E'``] ``=` `'@'` `# Function Call``generateLetters(S, ``0``, M);` `# This code is contributed by _saurabh_jaiswal.`

## C#

 `// C# program for the above approach` `using` `System;``using` `System.Collections.Generic;` `class` `GFG{` `// Function to generate all possible``// string by replacing the characters``// with mapped symbols``static` `void` `generateLetters(``string` `S, ``int` `P,``                     ``Dictionary<``char``, ``char``> M)``{``    ``// Base Case``    ``if` `(P == S.Length) {``        ``Console.WriteLine(S);``        ``return``;``    ``}` `    ``// Function call with the P-th``    ``// character not replaced``    ``generateLetters(S, P + 1, M);` `    ``// Replace the P-th character``   ``S = S.Substring(0, P) + M[S[P]] + S.Substring(P + 1);` `    ``// Function call with the P-th``    ``// character replaced``    ``generateLetters(S, P + 1, M);` `    ``return``;``}` `// Driver Code``public` `static` `void` `Main()``{``    ``string` `S = ``"aBc"``;``    ``Dictionary<``char``, ``char``> M = ``new` `Dictionary<``char``,``char``>();``    ``M.Add(``'a'``,``'\$'``);``    ``M.Add(``'B'``,``'#'``);``    ``M.Add(``'c'``,``'^'``);``    ``M.Add(``'d'``,``'&'``);``    ``M.Add(``'1'``,``'*'``);``    ``M.Add(``'2'``,``'!'``);``    ``M.Add(``'E'``,``'@'``);` `    ``// Function Call``    ``generateLetters(S, 0, M);` `}``}` `// This code is contributed by SURENDRA_GANGWAR.`

## Javascript

 ``
Output:
```aBc
aB^
a#c
a#^
\$Bc
\$B^
\$#c
\$#^```

Time Complexity: O(N*2N)
Auxiliary Space: O(1)

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