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# GCD of two numbers in PL/SQL

• Last Updated : 12 Jul, 2018

Prerequisite PL/SQL introduction
In PL/SQL code groups of commands are arranged within a block. A block group related declarations or statements. In declare part, we declare variables and between begin and end part, we perform the operations.

Given two numbers and task is to find the GCD (Greatest Common Divisor) or HCF (Highest Common Factor) value of the numbers.
Examples:

```Input:  num1 = 4, num2 = 6
Output: gcd of (num1, num2) = 2

Input: num1 = 8, num2 = 48
Output: gcd of (num1, num2) = 8
```

Approach is to take two numbers and find their GCD value using Euclidean algorithm.

Below is the required implementation:

 `DECLARE` ` ` `    ``-- declare variable num1, num2 and t ``    ``-- and these three variables datatype are integer  ``    ``num1 ``INTEGER``; ``    ``num2 ``INTEGER``; ``    ``t    ``INTEGER``; ``BEGIN` `    ``num1 := 8; `` ` `    ``num2 := 48; `` ` `    ``WHILE MOD(num2, num1) != 0 LOOP ``        ``t := MOD(num2, num1); `` ` `        ``num2 := num1; `` ` `        ``num1 := t; ``    ``END` `LOOP; `` ` `    ``dbms_output.Put_line(``'GCD of '` `                         ``||num1 ``                         ``||``' and '` `                         ``||num2 ``                         ``||``' is '` `                         ``||num1); ``END``; `` ` `-- Program End `

Output :

```GCD of 8 and 48 is 8
```

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