GATE | Sudo GATE 2020 Mock III (24 January 2019) | Question 43

Consider a network path with three links.

Link 1 – Speed : 10 Gbps, Propagation Delay : 40ms
Link 2 – Speed : 2 Gbps, Propagation Delay : 5ms
Link 3 – Speed : 2 Gbps, Propagation Delay : 10ms 

Assume processing delay to be zero. A data packet of 500 KB is sent from a source to a destination via the path:

link 1 – link 3 – link 2 

What is the total delay in transmitting the packet ?
(A) 54.90 ms
(B) 50.20 ms
(C) 55.55 ms
(D) 59.40 ms


Answer: (D)

Explanation: Total delay,

= Propagation delay + Transmission Delay + Queuing delay + Processing delay
= 40ms + 10ms + 5ms + 500KB X (1/10Gbps + 1/2Gbps + 1/2Gbps)
= 59.40 ms 

Note that here, ‘B’ is bytes (in data) and ‘b’ is bits (in speed).

Option (D) is correct.

Quiz of this Question

My Personal Notes arrow_drop_up
Article Tags :

Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.