GATE | Sudo GATE 2020 Mock I (27 December 2019) | Question 9

Solve:

1/logab(abcd) + 1/logbc(abcd) + 1/logcd(abcd) + 1/logda(abcd) 

(A) 10
(B) 1
(C) 4
(D) 2


Answer: (D)

Explanation:

= logabcd(ab) + logabcd(bc) + logabcd(cd) + logabcd(da)
= logabcd(ab * bc * cd * da)
= logabcd(abcd)2
= 2 logabcd(abcd)
= 2 

So, option (D) is correct.


Quiz of this Question

Attention reader! Don’t stop learning now.  Practice GATE exam well before the actual exam with the subject-wise and overall quizzes available in GATE Test Series Course.

Learn all GATE CS concepts with Free Live Classes on our youtube channel.