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GATE | Gate IT 2007 | Question 59

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  • Last Updated : 14 Feb, 2018

In the waveform (a) given below, a bit stream is encoded by Manchester encoding scheme. The same bit stream is encoded in a different coding scheme in wave form (b). The bit stream and the coding scheme are

2007_61
(A) 1000010111 and Differential Manchester respectively
(B) 0111101000 and Differential Manchester respectively
(C) 1000010111 and Integral Manchester respectively
(D) 0111101000 and Integral Manchester respectively


Answer: (A)

Explanation: In simple language, Manchester encoding has +A to -A transition for the clock cycle for which bit is ‘1’ and transition from -A to +A for the cycle when bit is ‘0’ (A is the amplitude).

kriti_9

kriti_10

The amplitudes are bipolar in Differential manchester encoding same as manchester encoding just that it toggles at ‘1’. When bit is ‘1’ we get transition from +A to -A and it remains the same until next ‘1’ arrives. The output changes to opposite transition (-A to +A) when next ‘1’ arrives.
The second encoding resembles the differential manchester code for the given number.

 

This solution is contributed by Kriti Kushwaha.

 

 

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