GATE | GATE IT 2006 | Question 42
A cache line is 64 bytes. The main memory has latency 32ns and bandwidth 1G.Bytes/s. The time required to fetch the entire cache line from the main memory is
(A) 32 ns
(B) 64 ns
(C) 96 ns
(D) 128 ns
Explanation: for 1 GBps bandwidth => it takes 1 sec to load 109 bytes on line
so, for 64 bytes it will take 64 * 1 /109 = 64 ns
main memory latency given is 32
so, total time required to place cache line is 64+32 = 96 ns
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