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GATE | Gate IT 2005 | Question 54
  • Last Updated : 28 Dec, 2015

The following C function takes a singly-linked list of integers as a parameter and rearranges the elements of the list. The list is represented as pointer to a structure. The function is called with the list containing the integers 1, 2, 3, 4, 5, 6, 7 in the given order. What will be the contents of the list after the function completes execution?

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struct node {
    int value; 
    struct node *next;
);
void rearrange (struct node *list) 
{
    struct node *p, *q;
    int temp;
    if (!list || !list -> next) 
        return;
    p = list; 
    q = list -> next;
    while (q) 
    {
        temp = p -> value;
        p -> value = q -> value;
        q -> value = temp;
        p = q -> next;
        q = p ? p -> next : 0;
    }
}

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(A) 1, 2, 3, 4, 5, 6, 7
(B) 2, 1, 4, 3, 6, 5, 7
(C) 1, 3, 2, 5, 4, 7, 6
(D) 2, 3, 4, 5, 6, 7, 1


Answer: (B)

Explanation: Please see  the link for more details  https://www.geeksforgeeks.org/pairwise-swap-elements-of-a-given-linked-list/

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