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GATE | Gate IT 2005 | Question 53
The following C function takes two ASCII strings and determines whether one is an anagram of the other. An anagram of a string s is a string obtained by permuting the letters in s.
int anagram (char *a, char *b) {
int count [128], j;
for (j = 0; j < 128; j++) count[j] = 0;
j = 0;
while (a[j] && b[j]) {
A;
B;
}
for (j = 0; j < 128; j++) if (count [j]) return 0;
return 1;
}
Choose the correct alternative for statements A and B.
(A)
A : count [a[j]]++ and B : count[b[j]]--
(B)
A : count [a[j]]++ and B : count[b[j]]++
(C)
A : count [a[j++]]++ and B : count[b[j]]--
(D)
A : count [a[j]]++and B : count[b[j++]]--
Answer
Please comment below if you find anything wrong in the above post
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