GATE | GATE-IT-2004 | Question 8
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Other way around:
x XOR y = x’y+xy’ = x’y+xy’+xx’+yy’ = (x+y) (x’+y’)
Using NAND gates
F= (x+y)(xy)’ = x. (xy)’ + y. (xy)’
F’= ( x. (xy)’ + y. (xy)’ )’ = (x. (xy)’)’. (y. (xy)’)
F=( (x. (xy)’)’. (y. (xy)’) )’
So Answer is B
Quiz of this Question
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