Skip to content
Related Articles

Related Articles

GATE | GATE CS 2021 | Set 1 | Question 63
  • Last Updated : 22 Mar, 2021
GeeksforGeeks - Summer Carnival Banner

A five-stage pipeline has stage delays of 150,120,150,160 and 140 nanoseconds. The registers that are used between the pipeline stages have a delay of 5 nanoseconds each.
The total time to execute 100 independent instructions on this pipeline, assuming there are no pipeline stalls, is _______ nanoseconds.
(A) 17160
(B) 16640
(C) 17640
(D) 15000

Answer: (A)

Explanation: Given : k=5, n=100

Total time=(k+n-1)*tp ,
where k=number of pipeline stages,
n=number of instructions,
tp=pipeline cycle time.

tp=max(stage delays) + register delay

Total time =(5+100-1)*165=104*165=17160 ns.

Quiz of this Question


My Personal Notes arrow_drop_up
Recommended Articles
Page :