GATE | GATE CS 2020 | Question 65
Consider a TCP connection between a client and a server with the following specifications; the round trip time is 6 ms, the size of the receiver advertised window is 50 KB, slow-start threshold at the client is 32 KB, and the maximum segment size is 2 KB. The connection is established at time t=0. Assume that there are no timeouts and errors during transmission.
Then the size of the congestion window (in KB) at time t+60 ms after all acknowledgements are processed is _________ .
Note – This question was Numerical Type.
Threshold = 32 Kb, MSS = 2KB, RTT = 6ms
Here, t + 60 is nothing but at the 10 RTT (60/6 = 10).
1st transmission: 2 KB 2nd transmission: 4 KB 3rd transmission: 8 KB 4th transmission: 16 KB 5th transmission: 32 KB (Threshold reached) 6th transmission: 34 KB 7th transmission: 36 KB 8th transmission: 38 KB 9th transmission: 40 KB 10th transmission: 42 KB
Now, after receiving acknowledgements of 10th transmission RTT = 10*6 = 60 ms.
And, after receiving acknowledgements of 10th transmission RTT (means at 11th transmission),
The congestion window size will be 44 KB.
Option (B) is correct.
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