Consider the Karnaugh map given below, where X represents “ don’t care” and blank represents 0.
Assume for all inputs (a, c, d) the respective complements (a’, b’, c’, d’)are also available. The above logic is implemented 2-input NOR gates only. The minimum number of gates required is ____________. Note: This questions appeared as Numerical Answer Type.
(A)
1
(B)
2
(C)
3
(D)
4
Answer: (A)
Explanation:
Answer: (A)
Output explanation:
Solving the above k- map, = ca’ Since complement of variables is also available. So, this can be implemented using one NOR gate. Therefore, option A is correct.
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Last Updated :
27 Sep, 2021
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