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GATE | GATE-CS-2016 (Set 1) | Question 57

  • Last Updated : 28 Jun, 2021

Consider a computer system with 40-bit virtual addressing and page size of sixteen kilobytes. If the computer system has a one-level page table per process and each page table entry requires 48 bits, then the size of the per-process page table is _________megabytes.
 
Note : This question was asked as Numerical Answer Type.
(A) 384
(B) 48
(C) 192
(D) 96


Answer: (A)

Explanation: Size of memory = 240
Page size = 16KB = 214
 
No of pages= size of Memory/ page size = 240 / 214 = 226
Size of page table = 226 * 48/8 bytes = 26*6 MB =384 MB
 
Thus, A is the correct choice.

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